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Firdavs [7]
2 years ago
6

A full truck weighed 3 2/6 tons. If the truck was only 4/6 full, how much would it weigh?

Mathematics
1 answer:
vaieri [72.5K]2 years ago
3 0
\frac{4}{6}*weight\ of\ truck=\frac{4}{6}*3\frac{2}{6}=\ \ \ \ | mke\ improper\ fractions\\\\
\frac{4}{6}*\frac{20}{6}=\frac{80}{36}=2\frac{2}{9}\\\\Now\ it\ weights\ 2\frac{2}{9}\ tons.
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Answer:

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Step-by-step explanation:

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Yanka [14]

Answer:

The coordinates of the image of the point (6,6) under the same  translation is: (9, 2)

Hence, option C is correct.

Step-by-step explanation:

The image of the point (2, 1) under a translation is (5, -3).

It means when we horizontally move 3 units to the RIGHT i.e. adding 3 units to the x-coordinate and vertically move 4 units DOWN i.e. subtracting 4 units from the y-coordinate of the original point (2, 1), we get the coordinates of the image (5, -3).

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The rule of translation can be formulated such as:

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Thus,

Under the same rule of translation, we can determine the coordinates of the image of the point (6,6):

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4 0
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