Question

A full truck weighed 3 2/6 tons. If the truck was only 4/6 full, how much would it weigh?

Answer 1

$\frac{4}{6}*weight\ of\ truck=\frac{4}{6}*3\frac{2}{6}=\ \ \ \ | mke\ improper\ fractions\\\\ \frac{4}{6}*\frac{20}{6}=\frac{80}{36}=2\frac{2}{9}\\\\Now\ it\ weights\ 2\frac{2}{9}\ tons.$