3 years ago

A full truck weighed 3 2/6 tons. If the truck was only 4/6 full, how much would it weigh?

1 answer:

3 0

$\frac{4}{6}*weight\ of\ truck=\frac{4}{6}*3\frac{2}{6}=\ \ \ \ | mke\ improper\ fractions\\\\
\frac{4}{6}*\frac{20}{6}=\frac{80}{36}=2\frac{2}{9}\\\\Now\ it\ weights\ 2\frac{2}{9}\ tons.$

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