Question

find the amount and the compound interest on rupees 12000 at 6% p.a. compounded half yearly for 3/2 years ​

Answer 1

Answer:

A= ₹3,112.72

CI = ₹1,112.72

Step-by-step explanation:

Here P = ₹ 12000

Since, interest is compounded half yearly.

Therefore, R = 6/2 = 3%

n = 3/2* 2 = 3 half years

$\because A= P\bigg(1+\frac{R}{100}\bigg)^n$

$\therefore A= 12000\times \bigg(1+\frac{3}{100}\bigg)^3$

$\therefore A= 12000\times \bigg(\frac{100+3}{100}\bigg)^3$

$\therefore A= 12000\times \bigg(\frac{103}{100}\bigg)^3$

$\therefore A= 12000\times \bigg(1.03\bigg)^3$

$\therefore A= 12000\times 1.092727$

$\therefore A= 13,112.724$

$\therefore A=Rs. \:13,112.72$

CI = A - P

CI = 13,112.72 - 12000

CI = ₹1,112.72