All categories

3 years ago

2p-q=0 find the subject formula for p and q

Mathematics

1 answer:

Lana71 [14]3 years ago

4 0

2p-q=0 => 2p=q => q/p=2

You might be interested in

What is 90/70 Simplified

allsm [11]

As an improper fraction, the simplified answer would be 9/7 after you divide both top and bottom by 10

------------------------

If you need a mixed number, then 9/7 converts to 1 & 2/7 because

9/7 = 1 remainder 2

If you had 9 cookies and 7 friends, then each friend gets 1 whole cookie, and there will be 2 left over.

3 0

4 years ago

Read 2 more answers

Multiply or divide as indicated. 10x^5 divide 2x^2

kenny6666 [7]

Answer:

5x^3(to the power of 3)

Step-by-step explanation:

10x^5/2x^2

divide the 10/2 like normal to get 5

x^5/x^2 (subtract the powers 5-2 when dividing powers)

you would get 5x^3

3 0

3 years ago

49y²+42y+9 please I need help, I promise to rate you as the brain lest when I get the exact answer am looking for

givi [52]

Answer:

$\huge\boxed{\sf (7y+3)(7y+3)}$

Step-by-step explanation:

$\sf = 49y^2+42y+9\\\\=(7y)^2+2(7y)(3)+(3)^2\\\\Using \ Formula \ a^2+2ab+b^2 = (a+b)^2\\\\= (7y+3)^2\\\\= (7y+3)(7y+3)\\\\\rule[225]{225}{2}$

Hope this helped!

4 0

3 years ago

Suppose y varies directy as x if x = 15 when y = 12 find x when y = 21

anastassius [24]

Answer:

26.25

Step-by-step explanation:

y=12

x=15

y=kx 12=k×15 k=12/15=4/5=0.8

21=0.8×x

21/0.8=26.25

6 0

3 years ago

Consider the probability that greater than 77 out of 131 computers will crash in a day. Assume the probability that a given comp

sweet-ann [11.9K]

Answer:

A Normal approximation to binomial cannot be applied to approximate the distribution of X, the number of computer crashes in a day.

Step-by-step explanation:

Let X = number of computers that will crash in a day.

The probability of a computer crashing in a day is, p = 0.99.

A random sample of n = 131 is selected.

A random computer crashing in a day is independent of the others.

The random variable X follows a Binomial distribution with parameters n = 131 and p = 0.99.

But the sample size is quite large, i.e. n > 30.

So the distribution of X can be approximated by the normal distribution if the following conditions are fulfilled:

np ≥ 10
n(1 - p) ≥ 10

Check whether the conditions satisfy or not:

$np=131\times 0.99=129.69>10\\n(1-p)=131\times (1-0.99)=1.31$

The second condition is not fulfilled.

A Normal approximation to binomial cannot be applied to approximate the distribution of X, the number of computer crashes in a day.

6 0

3 years ago