(x - 2)² + (y - 6)² = 4
You can be certain about one thing just by looking at the equation (2, 6) is the center, so, obviously the circle isnt going through this point
Since the radius is 2 if we don't move from y = 6 we have points in (0, 6) and (4, 6)
So alternative b.
To be more certain just subs the point in the x and y, if its equal, it pass through
(x - 2)² + (y - 6)² = 4
To point (4, 6)
(4 - 2)² + (6 - 6)² = 4
(2²) + 0² = 4
4 = 4
Thats right
We know that
if two lines are perpendicular
then
the slopes
m1*m2=-1
step 1
find the slope AB
A (0,2)
B (-3,-3)
m=(y2-y1)/(x2-x1)-----> m=(-3-2)/(-3-0)-----> m=-5/-3----> m1=5/3
step 2
find the slope CD
C (-4,1)
D (0,-2)
m=(y2-y1)/(x2-x1)-----> m=(-2-1)/(0+4)-----> m=--3/4----> m2=-3/4
step 3
multiply mi*m2
(5/3)*(-3/4)-----> -15/12
so
15/12 is not -1
therefore
AB is not perpendicular to CD
The number of members in 20 families in a village is given as 6,8,6,3,2,5,7,8,6,5,5,7,7,8,6,6,7,7,6,5
svetoff [14.1K]
Answer:
2
6,6,6,6,6,6=more than 5
7,7,7,7,7=has exactly 5 members
#1 first we need to solve for slope which is y2-y1/x2-x1
plug in the coordinates and get 1-6/5-(-2) which makes our slope -5/7
then use the equation for point slope form which is:
y-y1=m(x-x1)
then plug in one of the coordinates, I'll use (-2,6), now we have
y-6=-5/7(x+2)
now to make this slope intercept, we just have to solve
y-6=-5/7x-10/7
y=-5/7x+4 4/7
repeat all these steps for 2 and 3
#2: slope = -13/5
plug it in to point slope and get: y+8=-13/5(x-3)
slope intercept:
y+8= -13/5x + 39/5
y= -13/5x -1/5
#3: slope = 3/4
point slope form: y-2=3/4(x-3)
slope intercept: y-2=3/4x-9/4 --> y=3/4x-1/4
Answer:
x= negative 3
Step-by-step explanation:
-6 divided by 2 is -3
