Answer: $6.99
Step-by-step explanation: each minute is 20 cents and the connection fee is .99 cents.
30x.20= 6.00
6.00 + .99 = $6.99
Answer:
a) 0 , 1
b) 0.56 , 0.06
Step-by-step explanation:
X = 0.2
Y = 0.3
Find the distribution of X + Y
<u>a) All the possible values of X + Y </u>
The possible values of X + Y are ; 0,1
<u>b) The probabilities that X + Y takes each of the values </u>
P(X+Y=0 ) = ( 1-0.2 )*(1-0.3) = 0.56
P( X +Y = 1) = 0.2*0.3 = 0.06
Thoughts: The best that I was able to do was simplify it in this form.
Answer: V
Answer:
32
Step-by-step explanation:
Answer:
Step-by-step explanation:
Assuming this integral:
![\int_{-\infty}^0 5 e^{60x} dx](https://tex.z-dn.net/?f=%20%5Cint_%7B-%5Cinfty%7D%5E0%205%20e%5E%7B60x%7D%20dx)
We can do this as the first step:
![5 \int_{-\infty}^0 e^{60x} dx](https://tex.z-dn.net/?f=%205%20%5Cint_%7B-%5Cinfty%7D%5E0%20e%5E%7B60x%7D%20dx)
Now we can solve the integral and we got:
![5 \frac{e^{60x}}{60} \Big|_{-\infty}^0](https://tex.z-dn.net/?f=%205%20%5Cfrac%7Be%5E%7B60x%7D%7D%7B60%7D%20%5CBig%7C_%7B-%5Cinfty%7D%5E0%20)
![\int_{-\infty}^0 5 e^{60x} dx = \frac{e^{60x}}{12}\Big|_{-\infty}^0 = \frac{1}{12} [e^{60*0} -e^{-\infty}]](https://tex.z-dn.net/?f=%20%5Cint_%7B-%5Cinfty%7D%5E0%205%20e%5E%7B60x%7D%20dx%20%3D%20%5Cfrac%7Be%5E%7B60x%7D%7D%7B12%7D%5CBig%7C_%7B-%5Cinfty%7D%5E0%20%3D%20%5Cfrac%7B1%7D%7B12%7D%20%5Be%5E%7B60%2A0%7D%20-e%5E%7B-%5Cinfty%7D%5D)
So then we see that the integral on this case converges amd the values is 1/12 on this case.