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anastassius [24]
3 years ago
6

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Mathematics
1 answer:
____ [38]3 years ago
6 0

Answer:

\int_{-\infty}^0 5 e^{60x} dx = \frac{1}{12}[e^0 -0]= \frac{1}{12}  

Step-by-step explanation:

Assuming this integral:

\int_{-\infty}^0 5 e^{60x} dx

We can do this as the first step:

5 \int_{-\infty}^0 e^{60x} dx

Now we can solve the integral and we got:

5 \frac{e^{60x}}{60} \Big|_{-\infty}^0

\int_{-\infty}^0 5 e^{60x} dx = \frac{e^{60x}}{12}\Big|_{-\infty}^0 = \frac{1}{12} [e^{60*0} -e^{-\infty}]

\int_{-\infty}^0 5 e^{60x} dx = \frac{1}{12}[e^0 -0]= \frac{1}{12}  

So then we see that the integral on this case converges amd the values is 1/12 on this case.

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18. One month, the Taylor family had cash receipts of $876.16. Their excess of cash receipts above cash payments was $56.14. Wha
Valentin [98]

$820.02

Step-by-step explanation:

Since the Taylor family had cash receipts of $876.16 and their excess of cash receipts above cash payments was $56.14.

The total cash payments for the month will be calculated as:

= $876.16 - $56.14

= $820.02

6 0
2 years ago
Please answer question now
nata0808 [166]

Answer:

469.42 ft²

Step-by-step explanation:

  • Law of sines;

         w/sin27 = 38/sin40

                   w = sin27*38/sin40

                    w = 26.84 ft

  • Angle x;

            ∡X = 180 - 27- 40 = 113º

  • Area;

              A = 0.5*(26.84)*(38)*sin(113)

            A = 469.42 ft²

8 0
2 years ago
In ∆ABC with m∠C = 90° the sides satisfy the ratio BC:AC:AB = 4:3:5. If the side with middle length is 12 cm, find: 1) The perim
olga55 [171]
*The side with the middle length is 12cm, therefore BC must be 12 cm

------------------------------------------------------------<span>
Ratio 
------------------------</span>---------------------------------<span>--
BC:AC:AB
  4 : 3 : 5

</span>-----------------------------------------------------------
<span>Find 1 share
</span>-----------------------------------------------------------<span>
Given that BC = 12 cm
4 shares = 12 cm
1 share = 12 ÷ 4 = 3cm

</span>-----------------------------------------------------------
Find AC (4 shares)
-----------------------------------------------------------<span>
3 shares = 3 x 3 = 9 cm
BC = 9cm

</span>-----------------------------------------------------------
<span>Find AB (5 shares)
</span>-----------------------------------------------------------<span>
5 shares = 5 x 3 = 15cm
AB = 15cm

</span>------------------------------------------------------------
Length
-----------------------------------------------------------
   BC   :  AC   :  AB
12cm  :  9cm : 15cm<span>

---------------------------------</span>---------------------------------<span>
Perimeter
</span>------------------------------------------------------------------
<span>12 + 9 + 15 = 36cm

</span>------------------------------------------------------------------
<span>Answer: The perimeter is 36cm
</span>------------------------------------------------------------------<span>

</span>------------------------------------------------------------------
<span>Area
</span>------------------------------------------------------------------
1/2 x 9 x 12 = 54cm²<span>

</span>------------------------------------------------------------------
Answer: Area = 54cm²
------------------------------------------------------------------<span>

Given that the biggest ratio is AB
</span>⇒AB is the hypotenuse
AB = 15 cm

------------------------------------------------------------------
Answer: Hypotenuse = AB = 15cm
------------------------------------------------------------------
8 0
3 years ago
Read 2 more answers
If L ll M solve for x and y
velikii [3]

Answer:

(8y+17)=(6x-7), now solve and

(3x-29)+(8y+17), now solve and yes,, plzz can you give one brainliest

7 0
2 years ago
What is the area of the figure below​
jek_recluse [69]

Answer:

Option A

Step-by-step explanation:

Area of the composite figure = Area of ΔABH + Area of BCGH + Area of ΔDEF

Area of ΔABH = \frac{1}{2}(\text{Base})(\text{Height})

                        = \frac{1}{2}(6)(8-5)

                        = 9 in²

Area of the trapezoid = \frac{1}{2}(CG+BH)(\text{Distance between these lines})

                                    = \frac{1}{2}(6+4)(5)

                                    = 25 in²

Area of ΔDEF = \frac{1}{2}(8)(6)

                       = 24 in²

Therefore, area of the given figure = 9 + 25 + 24

                                                          = 58 in²

Option A will be the correct option.

3 0
2 years ago
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