Answer:
g(x) = x+1
Step-by-step explanation:
Informally, you can see that the function h(x) takes the root of a value that is 1 more than the value under the same radical in f(x). This suggests that adding 1 to x in f(x) will give you h(x). That is, ...
h(x) = f(x+1) = f(g(x))
so
g(x) = x+1
_____
More formally, you can apply the inverse of the function f(x) to the equation ...
h(x) = f(g(x))
f^-1(h(x)) = f^-1(f(g(x))) . . . inverse function applied
f^-1(h(x)) = g(x) . . . . . . . . . simplified
Now f^-1(x) can be found by solving for y in ...
x = f(y)
x = ∛(y+2) . . . . . . . . . definition of f(y)
x^3 = y+2 . . . . . . . . . cube both sides
x^3 -2 = y = f^-1(x) . . . subtract 2 from both sides
So, f^-1(h(x)) is ...
f^-1(h(x)) = g(x) = (∛(x+3))^3 -2 = x+3 -2
g(x) = x+1
50 tens
5000 thousands
50000 ten thousand
50 tens
5
Hope this helps
Answer:M(-0,5;0)
Step-by-step explanation:
<u>Answer:</u>
<u>(6x^(3)+11x^(2)-19x+5)-:-(3x-2)</u>
<u>Step-by-step explanation:</u>
for some reason it showed that but yeah hope this helps!
Answer:
x=square root 63. Basically the radical 63.
Step-by-step explanation:
So in the first triangle with the 3 in it. You have root 3 and use the a^2 +b^2=c^2 formula. So 3^2 + 3^2= x^2 and then when you solve you get radical 18^2 which is equal to radical 18 or square root 18. Then we go to the bigger triangle and we do the same formula but this time we have the c value which is 9. So we do radical 18^2 + x^2 = 9^2 and then solve that and minus 18 from the 81 since the radical goes off the 18 and you get square root63.
Sorry i couldn't use the signs. Sorry If I'm wrong Hope this helps!.
