Answer:
3rd Option is correct.
Step-by-step explanation:
Given Equation:
x² - 16x + 12 = 0
First We need to find solution of the given equation.
x² - 16x + 12 = 0
here, a = 1 , b = -16 & c = 12
Now,
Option 1).
( x - 8 )² = 144
x - 8 = ±√144
x - 8 = ±12
x = 8 + 12 = 20 and x = 8 - 12 = -4
Thus, This is not correct Option.
Option 2).
( x - 4 )² = 4
x - 4 = ±√4
x - 4 = ±2
x = 4 + 2 = 6 and x = 4 - 2 = 2
Thus, This is not correct Option.
Option 3).
( x - 8 )² = 52
x - 8 = ±√52
x - 8 = ±2√13
x = 8 + 2√13 and x = 8 - 2√13
Thus, This is correct Option.
Option 4).
( x - 4 )² = 16
x - 4 = ±√116
x - 4 = ±4
x = 4 + 4 = 8 and x = 4 - 4 = 0
Thus, This is not correct Option.
Therefore, 3rd Option is correct.
The first one is true your welcome hope thi helps
Answer:
4*x^4*y^22
Step-by-step explanation:
Your goal here is to REDUCE the given expression to simplest terms.
One way in which to approach this problem would be to rewrite (2x^2y^10)^3 as: (2x^2*y^8)*y^2*(2x^2*y^10)^2.
Dividing this rewritten expression by 2x^2*y^8 results in:
y^2(2x^2*y^10)^2.
We now need to raise (2x^2*y^10) to the power 2. Doing this, we get:
4x^4*y^20.
Multiply this by y^2 (see above):
y^2*4x^4*y^20
The first factor is 4: 4y^2*x^4*y^20. This is followed by the product of y^2 and y^20: 4*y^22*x^4
Finally, this should be re-written as
4*x^4*y^22
Another way of doing this problem would involve expanding the numerator fully and then cancelling out like factors:
8*x^6*y^30 4*x^4*y^22
----------------- = ------------------ = 4*x^4*y^22
2x^2y^8 1
Answer:
the correct answer for that would be identity property
Three times the difference of a number n and 1
