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marin [14]
2 years ago
6

Algorithm to calculate the area of a square.​

Computers and Technology
1 answer:
podryga [215]2 years ago
6 0

Answer:

length = int(input("Enter a length "))

width = int(input("Enter a width "))

area = length * width

print("The area is " + area)

You might be interested in
What will be displayed after code corresponding to the following pseudocode is run? Main Set OldPrice = 100 Set SalePrice = 70 C
Tatiana [17]

Answer:

A jacket that originally costs $ 100 is on sale today for $ 80                                    

Explanation:

Main : From here the execution of the program begins

Set OldPrice = 100  -> This line assigns 100 to the OldPrice variable

Set SalePrice = 70   -> This line assigns 70to the SalePrice variable

Call BigSale(OldPrice, SalePrice)  -> This line calls BigSale method by passing OldPrice and SalePrice to that method

Write "A jacket that originally costs $ ", OldPrice  -> This line prints/displays the line: "A jacket that originally costs $ " with the resultant value in OldPrice variable that is 100

Write "is on sale today for $ ", SalePrice  -> This line prints/displays the line: "is on sale today for $ " with the resultant value in SalePrice variable that is 80

End Program -> the main program ends

Subprogram BigSale(Cost, Sale As Ref)  -> this is a definition of BigSale method which has two parameters i.e. Cost and Sale. Note that the Sale is declared as reference type

Set Sale = Cost * .80  -> This line multiplies the value of Cost with 0.80 and assigns the result to Sale variable

Set Cost = Cost + 20  -> This line adds 20 to the value of Cost  and assigns the result to Cost variable

End Subprogram  -> the method ends

This is the example of call by reference. So when the method BigSale is called in Main by reference by passing argument SalePrice to it, then this call copies the reference of SalePrice argument into formal parameter Sale. Inside BigSale method the reference &Sale is used to access actual argument i.e. SalePrice which is used in BigSale(OldPrice, SalePrice) call. So any changes made to value of Sale will affect the value of SalePrice

So when the method BigSale is called two arguments are passed to it OldPrice argument and SalePrice is passed by reference.

The value of OldPrice is 100 and SalePrice is 70

Now when method BigSale is called, the reference &Sale is used to access actual argument SalePrice = 70

In the body of this method there are two statements:

Sale = Cost * .80;

Cost = Cost + 20;

So when these statement execute:

Sale = 100 * 0.80 = 80

Cost = 100 + 20 = 120

Any changes made to value of Sale will affect the value of SalePrice as it is passed by reference. So when the Write "A jacket that originally costs $ " + OldPrice Write "is on sale today for $ " + SalePrice statement executes, the value of OldPrice remains 100 same as it does not affect this passed argument, but SalePrice was passed by reference so the changes made to &Sale by statement in method BigSale i.e.  Sale = Cost * .80; has changed the value of SalePrice from 70 to 80 because Sale = 100 * 0.80 = 80. So the output produced is:

A jacket that originally costs $ 100 is on sale today for $ 80                              

7 0
3 years ago
A strategic business unit​ (SBU) of a major corporation has high market share in its​ industry, but the growth rate of the indus
VLD [36.1K]

Answer:

Cash cow

Explanation:

A cash cow is seen or made reference to as that part of a business, investment, or product that provides a steady income or profit.

Basically a cash cow is a business unit, product line, or investment that has a return on assets (ROA) greater than the market growth rate. This is expressed with an Idiom to mean that it produces "milk" that is profit long after the cost of the investment has been recouped.

The strategic business unit of this organization having high market share in its​ industry, but the growth rate of the industry is expected to be stagnant over the long run is simply yielding steady profit for the corporation through its high market value and this will continue for longer because it has to be at that high rate for a long period of time.

The SBU can be categorised as acting as the cash cow for that corporation.

6 0
3 years ago
Read 2 more answers
A(n) __________ is a common list operation used in programming. Its purpose is to iterate through a list of items, one item at a
34kurt
Linear search

You implement this algorithm by iterating over each item, and checking if the item matches what you are searching for.

It is linear because it takes a linear amount of time to search for an item.
5 0
2 years ago
To plan a pizza party, one may want to order enough pizza for everyone. Use the slicesPerPizza, slicesPerGuest, and totalGuests
attashe74 [19]

Answer:

import java.util.Scanner;

public class num6 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter number of guest");

   int totalGuest = in.nextInt();

       System.out.println("Enter number of slices per guest");

   int slicesPerGuest = in.nextInt();

       System.out.println("How many Slices are on a pizza");

   int slicesPerPizza = in.nextInt(); // Assume each pizza has 5 slices

   double pizzasNeeded;

       //Calculating the pizza Needed

    int totalslicesNeeded  = totalGuest * slicesPerGuest;

    pizzasNeeded = totalslicesNeeded/slicesPerPizza;

       System.out.println(pizzasNeeded);

   }

}

Explanation:

In this program User is required to enter values for the variables totalGuest, slicesPerGuest  and slicesPerPizza

First calculate the totalSlices needed by totalGuest * slicesPerGuest;

The calculate number of pizzas needed by totalslicesNeeded/slicesPerPizza;

4 0
3 years ago
Professor Midas drives an automobile from Newark to Reno along Interstate 80. His car’s gas tank, when full, holds enough gas
zmey [24]

Answer:

The GREEDY Algorithm

Explanation:

Based on the situation given in question, the Greedy algorithm shall give the optimal solution to professor

Suppose that the cities are at locations0 =x0< x1< . . . < x

We shall use the induction method to prove that G is the optimal solution valid for numbers less than n

We assume another solution Z which we initially consider to be optimum as well, based on that when Z fills the tank, it fills it to full level

Let us state the values in case of n intervals. Given below, we say that g1 is the first stop and z1 is also the first stop.

This can be written as ;

G=g1, g2, . . . , gk

Z=z1, z2, . . . , zk’

Here k’ <= k and k < n

Let I be an idex where for the first time gi is not equal to zi

Considering t= maxi Zi

Z′=g1, z2, z3, . . . , zk′

Now since z2, z3, . . . , zk′ should be an optimal stopping pattern for the problem otherwise we have chosen Z, with smaller gas filling (not feasible)

Using induction hypothesis we conclude thatg2, . . . , gk is an optimal stopping pattern, which is based on greedy algorithm

7 0
3 years ago
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