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lozanna [386]
3 years ago
9

I’m really bad at the nth term, can anyone help me figure out the nth term of this sequence: 7,10,13,16,19 ...

Mathematics
2 answers:
Debora [2.8K]3 years ago
6 0

Answer:

so the answer is 31

Step-by-step explanation:

well first you have to see how much it increases each time

_____________________________________________

so that would be three

_____________________________________________

so

7_10_13_16_19_22_25_28_31

1    2   3    4   5    6     7     8    9

Rainbow [258]3 years ago
6 0

Answer:

a_{n} = 3n + 4

Step-by-step explanation:

The terms of the sequence form an arithmetic sequence with n th term

a_{n} = a + (n - 1)d

where a is the first term and d the common difference

d = 10 - 7 = 13 - 10 = 3 and a = 7, hence

a_{n} = 7 + 3(n - 1) ← distribute and simplify

                        = 7 + 3n - 3 , hence

a_{n} = 3n + 4

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Step-by-step explanation:

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Find the distance between the points (1, 7) and (10, 1)<br> Please help:)
klio [65]

Answer:

<em>The distance between the points (1, 7) and (10, 1) is 10.82 units</em>

Step-by-step explanation:

<u>Distance between two points </u>

The distance between points A(x,y) B(w,z) can be calculated with the formula:

d=\sqrt{(z-y)^2+(w-x)^2}

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d=\sqrt{(1-7)^2+(10-1)^2}

d=\sqrt{(-6)^2+(9)^2}

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7 0
3 years ago
Part I
Crazy boy [7]

Answer:

130

Step-by-step explanation:

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2 years ago
Which is the solution to (8.5 x 103)(2 x 105) expressed in scientific notation?
kenny6666 [7]

We have been given an expression (8.5\times 10^3)(2\times 10^5). We are asked to find the solution to our given expression expressed as scientific notation.

Let us simplify our given expression.

Using exponent property a^m\cdot a^n=a^{m+n}, we will get:

8.5\times 2\times 10^3\times 10^5

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Now to write our answer in scientific notation, we need our 1st multiple between 1 and 10. So we will rewrite our expression as:

1.7\times 10\times 10^{8}

1.7\times 10^{1+8}

1.7\times 10^{9}

Therefore, our required solution would be 1.7\times 10^{9}.

8 0
2 years ago
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