Answer:
a) P(0 < X) = 0.5
b) P(0.5 < X) = 0.4375
c) P(-0.5 = X = 0.5) = 0.125
d) P(X< -2) = 0
e) P(X < 0 or X>-0.5) = 1
f) value of x is -0.9654
Step-by-step explanation:
Given that;
f(x) = 1.5x²
Now. the probabilities would be the integral of the given function from (-1 to 1)
a) P(0 < X)
P(X > 0)
⇒ Integral from 0 to 1 of f(x)
= (1/2)x³
= 1/2 - 0
= 0.5
Therefore; P(0 < X) = 0.5
b) P(0.5 < X)
P(X > 0.5)
this will also be done in the same way except that, the limits changes to { 0.5 to 1]
= (1)³/2 - (0.5)³ /2
= 0.4375
Therefore; P(0.5 < X) = 0.4375
c) P(-0.5 = X = 0.5)
The limits become [-0.5 , 0.5]
= (0.5)³/2 - (-0.5)³/2
= 0.125
Therefore; P(-0.5 = X = 0.5) = 0.125
d) P(X<-2)
since value of f(x) = 0 in that region
Therefore P(X< -2) = 0
e) P(X < 0 or X>-0.5)
= P(X < 0) + P(X > -0.5) - P( -0.5 < X < 0 )
= 0.5 + 0.5625 - 0.0625
= 1
Therefore; P(X < 0 or X>-0.5) = 1
f) Determine x such that P(x < X) = 0.05.
Let the value be 'a'
Then, integral from -1 to a will = 0.05
a³ - (-1)³ = 0.05 × 2
a³ + 1 = 0.10
a³ = 0.10 - 1
a³ = -0.9
a = ∛-0.9
a = -0.9654
Therefore, value of x is -0.9654
