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Hunter-Best [27]
2 years ago
9

Which compound inequality is equivalent to | ax -b | > C for all real numbers a, b, and c, where c>0?

Mathematics
1 answer:
My name is Ann [436]2 years ago
8 0

Hello,

Answer D

ax-b < -c or ax-b >c

If ax-b >0 then |ax-b| = ax-b ==> ax-b > c

if ax-b <0 then |ax-b|=-(ax-b) > c ==> ax-b <-c

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8 0
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a

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7 0
3 years ago
I need help on this question so if u actually can answer it correctly and show how you got it that would be helpful thx
Sedaia [141]

\rm \looparrowright -  \frac{1}{4} (8 - 4 + 20x)

Subtract the numbers

\rm \looparrowright -  \frac{1}{4} (4+ 20x)

Factor out 4 from the expression

\rm \looparrowright   - \frac{1}{ \cancel4}  \times  \cancel4(1 + 5x)

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When there is a - in front of an expression in parentheses, change the sign of each term in the expression to -

\rm \looparrowright   - 1  -  5x

  • <em>Thus, Options A and F are correct!!~</em>
6 0
2 years ago
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PilotLPTM [1.2K]

Answer:

Are ni =)

Step-by-step explanation:

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8 0
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Read 2 more answers
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Lubov Fominskaja [6]

Answer:

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