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larisa [96]
2 years ago
14

How many solutions will there be to the following equation?

Mathematics
1 answer:
zmey [24]2 years ago
4 0

Answer:

d. 2 solutions

+5/2,-5/2

Step-by-step explanation:

16x^2 = 100

x^2=100/16

x^2=25/4

X=√25/4

X=. +5/2,-5/2

So the answer is +5/2,-5/2

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the main and original incentive for european countries to explore was ___. curiosity religion trade warfare
KATRIN_1 [288]
The correct answer that would best fit the given statement above is the third option: trade. The main and original incentive for European countries to explore was trade. At present, there are several multi-lateral free trades in Europe. They are committed to the promotion of open and fair trade with all its partners. 
5 0
3 years ago
Read 2 more answers
Write an inequality?
Assoli18 [71]

Answer:

1\leqx\leq3

Step-by-step explanation:

This inequality shows that the values of x lie between 1 and 3 and they can be of values 1,2 or 3

5 0
2 years ago
Evaluate the integral Integral from 0 to 1 Integral from 0 to 3 Integral from 3 y to 9 StartFraction 6 cosine (x squared )Over 5
Natalka [10]

Answer:

\int^1_0\int^3_0\int^9_{3y}\frac{6 cos x^2}{5\sqrt z}dxdydz =\frac{18}{5}(1+\frac{sin2}{2})

Step-by-step explanation:

cosine x²= cos x²

Rule

  • \int x^ndx= \frac{x^{n+1}}{n+1}+c
  • \int cos \ mx \ dx = \frac{sin \ mx}{m}+c
  • \int \frac{1}{\sqrt x}dx = \frac{\sqrt x}{\frac{1}{2}}  +c= 2\sqrt x+c

Given that,

\int^1_0\int^3_0\int^9_{3y}\frac{6 cos x^2}{5\sqrt z}dxdydz

=\int ^1_0[\int^3_0(\int^9_{3y} \frac{6cos x^2}{5\sqrt z}dz)dy]dz

=\int^1_0[\int^3_0([\frac{6cos x^2 \times \sqrt z}{5\times \frac{1}{2}}]^9_{3y})dy]dx

=\int^1_0[\int^3_0([\frac{12cos x^2 \times( \sqrt 9-\sqrt{3y})}{5}])dy]dx

=\int^1_0[\int^3_0([\frac{12cos x^2 \times( 3-\sqrt{3y})}{5}])dy]dx

=\int^1_0[\frac{12cos x^2 \times( 3y-\frac{\sqrt{3}y^\frac{3}{2}}{\frac{3}{2}})}{5}]^3_0dx

=\int^1_0[\frac{12cos x^2 \times( 3.3-\frac{2\sqrt{3}.3^\frac{3}{2}}{3})}{5}]^3_0dx

=\int^1_0[\frac{12cos x^2 \times( 9-6)}{5}]dx

=\frac{18}{5}\int^1_02cos x^2dx

=\frac{18}{5}\int^1_0(1+cos2x)dx

=\frac{18}{5}[(x+\frac{sin2x}{2})]^1_0

=\frac{18}{5}(1+\frac{sin2}{2})

6 0
3 years ago
bob bought bill an item that cost 193. bill gave him 200. bob then took 100 out of the 200 to buy bill an item for 93. how much
jekas [21]

Answer:Bob Owes $186 to the store he purchased an item at

Step-by-step explanation:

5 0
3 years ago
Finding the sums
Sav [38]

The sum of the first 7 terms of the geometric series is 15.180

<h3>Sum of geometric series</h3>

The formula for calculating the sum of geometric series is expressed according to the formula. below;

GM = a(1-r^n)/1-r

where

r is the common ratio

n is the number of terms

a is the first term

Given the following parameters from the sequence

a = 1/36

r = -3

n = 7

Substitute

S = (1/36)(1-(-3)^7)/1+3
S = 1/36(1-2187)/4
S = 15.180

Hence the sum of the first 7 terms of the geometric series is 15.180

Learn more on sum of geometric series here: brainly.com/question/24221513

#SPJ1

7 0
1 year ago
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