How long is 9/10 inches

1 answer:

8 0

-- It's exactly 10% shorter than 1 inch, and 92.5% shorter than 1 foot.

-- It's also approximately 0.01343 smoot (rounded).

-- It's also approximately 2.286 centimeters, or 22.86 millimeters,
or 0.0000142 mile.

-- It's also approximately 0.000 000 000 000 000 002 418 light-year.

You see, "9/10 inch" is known and understood precisely wherever inches are
used in the world (everywhere throughout Liberia, Burma, and the USA) exactly
because "inch" is a unit that's exactly defined and agreed on in all those places.
But when you come along and say "I don't know what an inch is, describe it to me
in terms of something else", then you throw people for a loop.

If you can tell us what other unit you want to measure with ... like a flower,
a finger, an animal, or something else that we're also familiar with, then
we'll compare "9/10 inch" to that item for you. But that won't be exact,
because all of those things come in different sizes, and none of them has
a standard size that everybody agrees on.

You might be interested in

Write an equation in point-slope form of the line that passes through the point (9,0) and has a slope of m=-3 .

aksik [14]

Answer:

$y = - 3x + 27$

Step-by-step explanation:

The standard form for the equation of the line is

$y = mx + c$

Recall that:

$y = 0 \: \: \: x = 9 \: \: \: m = - 3 \\ y = mx + c \\ 0 = - 3(9) + c \\ 0 = - 27+ c \\ 27 = c$

Therefore the equation of the line is:

$y = mx + c \\ y = - 3x + 27$

5 0

2 years ago

9. Gold miners in Alaska have found, on average, 12 ounces of gold per 1000 tons of dirt excavated with a standard deviation of

netineya [11]

Answer:

9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 12, \sigma = 3$