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Lera25 [3.4K]
3 years ago
6

-x + 5y = 13x - y = 15​

Mathematics
2 answers:
aev [14]3 years ago
4 0
To find x we would make x-y=15 into x=15+y so we can have an equation for x. We plug in for x in the other equation and we have -(15+y)+5y=13. We distribute the - sign to get -15-y+5y=13. We subtract a y from 5y and we have -15+4y=13. We add 15 to both sides to cancel out the negative 15. We get 4y=28. We divide by 4 to both sides to cancel out multiplying by 4. We get y as 7. Now, to get x we simply look back at the equation x-y=15. We plug 7 making x-7=15. Instead of subtracting we add 7 to both sides and we get x as 22. Therefore, x is 22 and y is 7
aivan3 [116]3 years ago
3 0

Answer:

x-y-15=15-15

x-y-15=0

hope this helps :)

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What is the correct expansion of (x - 2)(x - 5)?
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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The equivalent expression is ~

  • {x}^{2}  - 7x + 10

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

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A fruit stand has to decide what to charge for their produce. They decide to charge \$5.30$5.30dollar sign, 5, point, 30 for 111
MAVERICK [17]

Answer:

a + b = 5.30

a + b = 7

No

Step-by-step explanation:

Expressing the information as system of linear equation :

Let apples = a, oranges = b

If $5.30 is charged for one apple and one orange, then we have ;

a + b = 5.30 - - - (1)

If $14 is charged for 2 apples and 2 oranges, then we have ;

2a + 2b = 14 - - - - (2)

a + b = 7

Since both equations gives varying combined cost for equal amount of the fruit, then a unique cost cannot be obtained for each fruit from the systems of equation using simultaneous equation process.

From (1)

a = 5.30 - b

Put a = 5.30 - b in (2)

2(5.30 - b) + 2b = 14

10.6 - 2b + 2b = 14

10.6 = 14 - - - - - (variables cancels out).

3 0
3 years ago
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