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Zepler [3.9K]
3 years ago
7

if a jar of coins contains 40 half dollars and 200 quarters, what is the monetary value of the coins? (Show all work)

Mathematics
1 answer:
diamong [38]3 years ago
4 0
40x50=2000
200x25=5000
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A regular workweek is 40 hours. Overtime pay is time and one-half): Manual is a word-processor operator. He makes $13.50 an hour
pychu [463]
Overtime is over 40 so subtract 40 from 54 and get
54-40=14
14 hours hovertime
so multipliy usuall pay by 40 (since worked 40 normal hours) then add to overtime pay by 14 hours so


(13.5 times 40)+(13.5 times 1.5 times 14)=
540+283.5=823.5
answer is $823.50

4 0
2 years ago
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Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Factorise 20x-28 help please it's maths
makvit [3.9K]
20 and 28 can be divided by 4, so just take the 4 out so the answer should be 4(5x - 7)
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3 years ago
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Nora got an allowance of 50¢ each weekday and 75¢ each weekend altogether how much do they get in:
Furkat [3]
A) > since it is 50c per weekday and 75c each weekend assuming it allows for the 2 days each saturday/sunday.
50c * 5 = $2.50 since there are 5 days in weekdays
75c * 2 = $1.50 since there are 2 days in the weekend
Add $2.50 and $1.50 to get $4.00

b) For 3 school days we know it is a weekday on the school week.
So perform 50c * 3 which gives us <span>$1.50

</span>c) 12 days off from school is 10 weekdays and 1 weekend or 2 days of 75c
So now just do 50c * 10 which is $5.00 and 75c * 2 which is $1.50
Add $5.00 and $1.50 and we get $6.50

d) 4 weeks = 20 weekdays since 5 *4 = 20 and 8 days in each weekend since 2 * 4 = 8
Now that we have the amount of weekdays and weekend days we can multiply.
50c * 20 = $10.00
75c * 4 = $3.00
Add $10.00 and $3.00 to get $13.00 for 4 weeks.

e) We have 1 day of the weekend and 2 weekdays here.
50c * 2 = $1.00
75c * 1 = 75c
<span>$1.00 + 75c = $1.75 in those 3 days listed.
</span>
Add all these together to get your total value.
$4.00 + $1.50 + $6.50 + $13.00 + $1.75 = $26.75

7 0
3 years ago
Can anyone answer this question please<br> 6[y-2]/7-12=2[y-7]/3
Kaylis [27]

Answer:

y =47.5.

Step-by-step explanation:

First eliminate the fractions by multiplying through by the LCM of 7 and 3 which is 21:

21* 6[y-2]/7-21*12 = 21*2[y-7]/3

18(y - 2) - 252 = 14(y - 7)

18y -36 - 252 = 14y - 98

18y - 14y = -98 + 36 + 252

4y = 190

y = 190/4

y = 47.5.

8 0
2 years ago
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