Using the formulas to find its length =
P= 2 ( l + w )
d= w² + l²
There are 2 solutions for,
l = P / 4 + 1 / 4 √8d² - p²
= 39.2 / 4 + 1 / 4 × √8 × 14² - 39²
= 11. 2 km answer.
Using the formula to find its width =
w = p / 2 - l
= 39.2 / 2 - 11.2
= 8.4 km answer.
≈ the length of a rectangle is 11.2 km and the width is 8.4 km
Answer:
Once.
Step-by-step explanation:
To find when they chirp together, we must find the LCM of the two numbers. The LCM, or least common multiple of 13 and 5 is 65. Therefore, after 65 minutes is the first time they chirp together. Then we can multiply 65 by 2 to see if they chirp a second time. 65x2 is 130, but 8AM-10AM is only 120 minutes, therefore they do not chirp together more than 1 time.
Answer:
The number is = 16
Step-by-step explanation:
Given:
Twice the sum of a number and 2 is equal to three times the difference of the number and 4.
To find the number.
Solution:
Let the number be = ![x](https://tex.z-dn.net/?f=x)
The equation can be now written as:
![2(x+2)=3(x-4)](https://tex.z-dn.net/?f=2%28x%2B2%29%3D3%28x-4%29)
Solving for ![x](https://tex.z-dn.net/?f=x)
Using distribution:
![2x+(2\times2)=3x-(3\times4)](https://tex.z-dn.net/?f=2x%2B%282%5Ctimes2%29%3D3x-%283%5Ctimes4%29)
![2x+4=3x-12](https://tex.z-dn.net/?f=2x%2B4%3D3x-12)
Adding 12 both sides.
![2x+4+12=3x-12+12](https://tex.z-dn.net/?f=2x%2B4%2B12%3D3x-12%2B12)
![2x+16=3x](https://tex.z-dn.net/?f=2x%2B16%3D3x)
subtracting
from both sides.
![2x-2x+16=3x-2x](https://tex.z-dn.net/?f=2x-2x%2B16%3D3x-2x)
![16=x](https://tex.z-dn.net/?f=16%3Dx)
∴ ![x=16](https://tex.z-dn.net/?f=x%3D16)
Thus, the number is = 16
Answer:
Step-by-step explanation:
-14rst + 22r²s - 4rs²t = -2 * 7 * rst + 2 *11 *r²s - 2 * 2 rs²t
= -2rs [ 7t -11r + 2st ]