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3 years ago

What is the scale factor

1 answer:

6 0

A scale factor is a number which scales, or multiplies, some quantity. In the equation y = Cx, C is the scale factor for x. ... The ratio of any two corresponding lengths in two similar geometric figures is also called a scale.

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Cubes are three-dimensional square shapes that have equal sides. What is the density of a cube that has a mass of 12.6 g and a m

Ymorist [56]

D = m / V
m = 1.26 g 
V = s^3 = 4.1^3 = 68.921 cm^3 
so 
D = 12.6 / 68.921 = 0.1828 g/cm^3 
and this corresponds to choice (a)

7 0

3 years ago

Read 2 more answers

Plz some one look at this

aleksklad [387]

5 : - 1/6 = 0.167 out of 10 = 1.67 out of 100 = 16.7

even number 0.33 out of 10:- 3.3 out of 100:- 33

a prime number 0.5 out of 10: 5 and out of 100:- 50

multipl of 3:- 0/33 out of 10:- 3.3 and out of 100: 33

4 0

3 years ago

Find all values of x in the interval [0, 2π] that satisfy the equation. 6sin²(x) = 3

34kurt

Answer:

The solutions are π/4, 3π/4,5π/4,7π/4

Step-by-step explanation:

The given equation is

6sin²(x) = 3

Divide by 6 to get:

${ \sin}^{2} (x) = \frac{1}{2}$

This implies that;

$\sin(x) = \pm \frac{ \sqrt{2} }{2}$

$\sin(x) = \frac{ \sqrt{2} }{2}$

$x = \frac{\pi}{4}$

in the first quadrant

$x = \frac{3\pi}{4}$

in the second quadrant.

$\sin(x) = - \frac{ \sqrt{2} }{2}$

$x = \frac{5\pi}{4}$

in the third quadrant

$x = \frac{7\pi}{4}$

5 0

3 years ago

Determine the equation of the circle graphed below. ( please help me )

Brums [2.3K]

Answer:

$Equation : \\(x+3)^2 + ( y -2)^2 = 36$

Step-by-step explanation:

For standard form the circle's equation we need the centre of the circle and the radius.

Step 1: Find the centre

If the centre is not given find the end points of the diameter

and then find the mid point.

Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )

The mid-point of the diameter is :

$Mid-point = (\frac{-3 + - 3}{2}, \frac{-4+8}{2}) = (-3, 2)$

Therefore, centre of the circle = ( -3 , 2 )

Step 2 : Find radius

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )

That is ,

$Diameter = \sqrt{(-3-(-3))^2 + ( -4 -8)^2}\\$

$= \sqrt{(-3 + 3)^2 + (-12)^2}\\\\=\sqrt{0 + 144}\\\\=12$

Therefore ,

$Radius = \frac{12}{2} = 6$

Step 3 : Equation of the circle

Standard equation of the circle with centre ( h ,k )

and radius ,r is :

$(x - h)^2+(y -k)^2 = r^2$

Therefore, the equation of the circle with centre ( -3, 2)

and radius = 6 is :

$(x - (-3))^2 + (y - 2)^2 = 6^2\\\\(x + 3)^2 + (y - 2)^2 = 36$

5 0

3 years ago

LIVE TEST NEED HELP Several students made comments about this image C B D Which comment is true? "If I know the measures of A an

Harlamova29_29 [7]

The last two are correct: “If I know the measures of Angles C and B, I can find the angles of A and D.” and “If I know the measure of angle A, I can find the measure of angle D by subtracting from 180”
Hope that helps: )

3 0

3 years ago

What is the scale factor ￼

What is the scale factor