This is the answer to your problem.
We know that
2π/3 radians-------> convert to degrees-----> 2*180/3---> 120°
120°=90°+30°
Part a) Find <span>sin(2π/3)
</span>sin(2π/3)=sin (90°+30°)
we know that
sin (A+B)=sin A*cos B+cos A*sin B
so
sin (90°+30°)=sin 90*cos 30+cos 90*sin 30
sin 90=1
cos 30=√3/2
cos 90=0
sin 30=1/2
sin (90°+30°)=1*√3/2+0*1/2-----> √3/2
the answer part a) is
sin(2π/3)=√3/2
Part b) Find cos (2π/3)
cos (2π/3)=cos (90°+30°)
we know that
cos (A+B)=cos A*cos B-sin A*sin B
so
cos (90°+30°)=cos 90*cos 30-sin 90*sin 30
sin 90=1
cos 30=√3/2
cos 90=0
sin 30=1/2
cos (90°+30°)=0*√3/2-1*1/2----> -1/2
the answer part b) is
cos (2π/3)=-1/2
Answer:
The 4th term of the linear sequence = 3
Step-by-step explanation:
First term, a = -9
Common difference, d = -5 - (-9)
= -5 + 9
= 4
d = 4
The 4th term of the linear sequence = a + (n - 1)d
where,
n = 4
a + (n - 1)d
= -9 + (4 - 1)4
= -9 + (3)4
= -9 + 12
= 3
The 4th term of the linear sequence = 3
7/12*6/14
7*6=42
12*14=168
=42/168
=0.25 =1/4
Answer:
The correct answer is "rational" . It is not an "integer" because it is a "decimal value". It is not "irrational" because the decimal value terminates and does not repeat.
