Answer:
<u>The perimeter of the square is option E. 16√5 mm.</u>
<u>The area of the square is option A. 80 mm².</u>
Step-by-step explanation:
1. Let's calculate the perimeter of this square:
The perimeter of a square is the sum of its side 4 times, thus:
Perimeter = 4√5 + 4√5 + 4√5 + 4√5
<u>Perimeter = 16 √5</u>
<u>Perimeter = 4 * 4√5 = 16√5</u>
<u>The correct answer is option E. 16√5 mm</u>
2. Let's calculate the area of this square:
The area of a square is the length of its side squared, thus:
Area = (4√5)²
Area = 4√5 * 4√5
Area = (4 * 4 * √5 * √5)
Area = 16 * 5 = 80
<u>The correct answer is A. 80 mm²</u>
Answer:
It decreased by 25%
Step-by-step explanation:
8 x .25=2
8 - 2 = 6
The tangent ratio is
tan(38°) = opposite/adjacent = (height of cliff)/(distance to base)
Multiplying the equation by the denominator gives
height of cliff = (80 ft)*tan(38°) ≈ 62.5 ft
Answer:
128 cm^2
Step-by-step explanation:
The area of a trapezoid is given by
A = 1/2 (b1+b2) h
where b1 and b2 are the lengths of the bases and h is the height
A =1/2( 10+22) * 8
A = 1/2 (32)8
= 128
Answer:
1.
Vert. asymptote: x = {-3, 2}
Horiz. asymptote: y = 0
x-int: None
Question 3.
a. There is no hole
b. Vert. asymptote: x = {-2, 2}
c. f(x) = 0: x = {0, -1/2}
d. The graph has no hole at (-2, 4)
Question 4.
a. Vert. asymptote: x = {-2, 2}
b. f(x) = 0: x = {0, -1/2}
c. Horizontal asymptote: y = 2
d. The graph has no hole
I'm a bit confused. Some of the things stated in the question aren't true like how there are holes in places where there aren't.
