Given the information for reaction 1 at a specific temperature; calculate kc for reaction 2 at the same temperature. reaction 1:

Question

Ber [7]

3 years ago

3

Given the information for reaction 1 at a specific temperature; calculate kc for reaction 2 at the same temperature. reaction 1:

2ch4 (g) ⇄ c2h2 (g) + 3h2 (g) kc = 0.020 reaction 2: 2c2h2 (g) + 6h2 (g) ⇄ 4ch4 (g)

Chemistry

2 answers:

GuDViN [60] · Answer 1 · 2022-04-27T07:03:23+03:00

Answer is: equilibrium constants is 2500.
Chemical reaction 1: 2CH₄(g) ⇄ C₂H₂(g) + 3H₂(g); Kc₁ = 0,020.
Chemical reaction 2: 2C₂H₂(g) + 6H₂(g) ⇄ 4CH₄(g); Kc₂ = ?
Chemical reaction 2 is reverse chemical reaction 1 multiply with two:
Kc₂ = 1 ÷ (Kc₁)².
Kc₂ = 1 ÷ (0,020)².
Kc₂ = 1 ÷ 0,0004.
Kc₂ = 2500 = 2,5·10³.

Marina86 [1] · Answer 2 · 2022-04-27T08:53:22+03:00

Kc for reaction 2 at the same temperature

$\large{\boxed{\bold{Kc~=~50^2~=~2500}}}$

$\boxed{\boxed{\bold{Further~explanation}}}$

The equilibrium constant or Kc is the price of the concentration product in the equilibrium state of the substance in the right segment divided by the product of the substance in the left section, each of which has a reaction coefficient raised

The equilibrium constant based on concentration (Kc) in a reaction

pA + qB -----> mC + nD

$\large{\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}$

$Unit~Kc~is~M ^{(p + q) - (m + n)}$

In reaction 1 2CH₄ (g) ⇄ C₂H₂ (g) + 3H₂ (g) Kc = 0.020

On reaction 2: 2C₂H₂ (g) + 6H₂ (g) ⇄ 4CH₄ (g)

From the 2 equation the above reaction shows that reaction 2 is the opposite of reaction 1 whose coefficient is multiplied by 2. Then the price of Kc reaction 2 is the square of the inverse price of Kc reaction 1

2CH₄ (g) ⇄ C₂H₂ (g) + 3H₂ (g) Kc = 0.020

$\large{\boxed{\bold{Kc~=~\frac{[C_2H_2][H_2]^3}{[CH_4]^2} }}}$