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Illusion [34]
3 years ago
7

How many grams of oxygen are formed when 8.20 moles of KOH are formed? 4 KO(s) + 2 H2O(l) → 4 KOH(s) + O2(g)

Chemistry
2 answers:
julia-pushkina [17]3 years ago
6 0

Answer : The mass of oxygen formed are 65.6 grams.

Explanation :

First we have to calculate the moles of O_2

The given balance chemical reaction is:

4KO(s)+2H_2O(l)rightarrow 4KOH(s)+O_2(g)

From the balanced chemical reaction we conclude that,

As, when 4 moles of KOH formed then 1 mole of O_2 will be formed

So, when 8.20 moles of KOH formed then \frac{8.20}{4}=2.05 mole of O_2 will be formed

Now we have to calculate the mass of O_2

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

Molar mass of O_2 = 32 g/mole

\text{ Mass of }O_2=(2.05moles)\times (32g/mole)=65.6g

Therefore, the mass of oxygen formed are 65.6 grams.

Pie3 years ago
3 0
49.7g02* that's the answer
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Answer:

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Explanation:

Complete Question

Soda are made fizzy by the carbon dioxide (CO₂) dissolved int he liquid. An amount of carbon dioxide equal to about 8.0 L of carbon dioxide gas at atmospheric pressure and 300.0 K can be dissolved can be dissolved in a 2-L bottle of soda. The molar mass of CO₂ IS 44 g/mol.

A) How many moles of carbon dioxode are in the 2-L? (1L = 0.001 m³)

B) What is the mass of the carbon dioxide in the 2-L bottle of soda?

Solution

Assuming that CO₂ is an ideal gas.

A) The amount of carbon dioxide in 2.0 L of soda bottle is equal to the amount of Carbon dioxide in about 8.0 L of carbon dioxide gas at atmospheric pressure and 300.0 K

From the ideal gas equation, we know that

PV = nRT

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V = volume of the gas = 8.0 L = 0.008 m³

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T = absolute temperature of the gas in Kelvin = 300 K

101325 × 0.008 = n × 8.314 × 300

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Hope this Helps!!!

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