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3 years ago

6

brad wants to open a new saving account. he finds one that returns 3% on his investment each year.Use the varibles to write a fo

rmula for the final balance after one year

1 answer:

Vsevolod [243]3 years ago

3 0

3% is the interest so you would do 3% of the investment plus the original investment so 3%×I=z and then z+I=the answer. sorry if this didnt help I'm new and I tried my best sorry!

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An above-ground swimming pool is leaking. The function h(d) = 48 - 1. 5d gives the height of the water in the pool in inches d d

MAXImum [283]

Answer:

A) 48 in : initial height of the water

B) 40.5 in : height of the water after 5 days

C) 32 days

D) Yes, should be restricted.

Domain: 0 ≤ d ≤ 32

Step-by-step explanation:

$h(d) = 48 - 1. 5d$

A)

$h(0) = 48 - 1. 5(0)=48$

48 in is the initial height of the water

B)

$h(5) = 48 - 1. 5(5)=48-7.5=40.5$

40.5 in is the height of the water after 5 days

C) when the pool is empty, h = 0.

So set the equation to zero and solve for d.

$\implies 48 - 1. 5d=0\\\\\implies 1.5d=48\\\\\implies d=\dfrac{48}{1.5}\\\\\implies d=32$

D) Yes, the domain should be restricted because when d > 32, h < 0 and the height of the water in the pool cannot be negative

Domain: 0 ≤ d ≤ 32

5 0

2 years ago

What is the rate for 4 shirts for $32:00

EastWind [94]

The answer should be $8 if you are trying to find the unit rate. All you have to do is divide 32 by 4 and you get 8. Hope that helped.

3 0

4 years ago

Read 2 more answers

Prove divisibility 45^45·15^15 by 75^30

Anuta_ua [19.1K]

Answer:

$3^{75}$

Step-by-step explanation:

We are asked to divide our given fraction: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(3*15)^{45}=3^{45}*15^{45}$

$75^{30}=(5*15)^{30}=5^{30}*15^{30}$

Substituting these values in our division problem we will get,

$\frac{3^{45}*15^{45}*15^{15}}{5^{30}*15^{30}}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$\frac{3^{45}*15^{45+15}}{5^{30}*15^{30}}$

$\frac{3^{45}*15^{60}}{5^{30}*15^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{45}*15^{60-30}}{5^{30}}$

$\frac{3^{45}*15^{30}}{5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{3^{45}*(3*5)^{30}}{5^{30}}$

$\frac{3^{45}*3^{30}*5^{30}}{5^{30}}$

Upon canceling out $5^{30}$ we will get,

$3^{45}*3^{30}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$3^{45+30}$

$3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

8 0

3 years ago

Find A. Round to the nearest tenth.

Marianna [84]

Answer:

27.8 degrees

Step-by-step explanation:

Wasn't it 'a,' not 'A,' that you wanted?

The ratio a/ 30 is the cosine of the angle 22 degrees, which in turn is 0.927:

a

Then 0.927 = ------- which yields a = 30(0.927) = 27.8 degrees

30

3 0

3 years ago

daniel’s print shop purchased a new printer for 35,000 each year it depreciates at a rate of 5% how much will the printer be wor

frutty [35]

Answer:

$23,219.72

Step-by-step explanation:

ab^x

a: initial value

b: value remaining after depreciation per year (in percentage)

x: number of years that have passed

35000(0.95)^8= 23219.7151

Round to the nearest hundredth value:

About $23219.72

4 0

3 years ago