Given:
The equation of the curve is:

To find:
The gradient (slope) of the given curve at point (2,7).
Solution:
We have,

Differentiate the given equation with respect to x.


Now we need to find the value of this derivative at (2,7).




Therefore, the gradient (slope) of the given curve at point (2,7) is 19.
Answer:
infinitely many solutions
Step-by-step explanation:
GIVEN:
We are given the following polynomial;

Required;
We are required to factorize this polynomial completely.
Step-by-step explanation;
To factorize this polynomial, we start by grouping;

We now take the common factor in each group;

Next, we factorize the first parenthesis. To do this we set the equation equal to zero and solve for x as follows;

Therefore, the factors of the other parenthesis are;

Therefore, the complete factorization of the polynomial is;
ANSWER:

Option C is the correct answer.
Answer:
Given an angle formed by two lines with a common vertex, this page shows how to ... The above animation is available as a printable step-by-step instruction sheet, which can be ... This construction works by creating two congruent triangles
Step-by-step explanation: