<h3><u>Question:</u></h3>
The formula h = 120t-16t^2 gives the height h in feet of an object t seconds after it is shot upward from Earth's surface with an initial velocity of 120 feet per second. What will the height of the object be after 6 seconds?
<h3><u>Answer:</u></h3>
The height of object after 6 seconds is 144 feet
<h3><u>Solution:</u></h3>
<em><u>The formula that gives the height of an object is:</u></em>

Where,
h is the height in feet and t is the time in seconds
To find: height of the object be after 6 seconds
To find the height of the object be after 6 seconds, substitute t = 6

Thus height of object after 6 seconds is 144 feet
Step-by-step explanation:
I have no idea if I'm doing it right but my guess would be to take the values that we get from f(x) and g(x) when x = 1. Therefore we get that f(x) is equal to 4 and g(x) is equal to -1. We than just do f/g which is 4/-1 which gives us the final answer of -4 which is option B.
Answer: Option B, -4