Answer:
b:4,5
Step-by-step explanation:
Answer:
no Solution
Step-by-step explanation:
-12x-12y=4\\ 3x+3y=0
12x-12y=4
add 12y to both sides
12x-12y+12y=4+12y
divid both sides by -12
\frac{-12x}{-12}=\frac{4}{-12}+\frac{12y}{-12}
simplfy
x=-\frac{1+3y}{3}
\mathrm{Substitute\:}x=-\frac{1+3y}{3}
\begin{bmatrix}3\left(-\frac{1+3y}{3}\right)+3y=0\end{bmatrix}
\begin{bmatrix}-1=0\end{bmatrix}
Answer:
I can’t answer
Step-by-step explanation:
Pls take a state photo I can’t tell if it is a rectangle or a polygon
X+x+1+x+2=51
3x+3=51
Use inverse operations to solve
subtract 3 from both sides
3x=48
Divide by 3 on both sides
x=16
16, 17, 18
1) (12p-3)(12p-3)
=144p^2-36p+36p+9
=144p^2+9 (-36+36=0 so it cancels out)
