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3 years ago

I need help with this 2 please

Mathematics

1 answer:

xeze [42]3 years ago

7 0

Answer:

Step-by-step explanation:

The formula for C is

C=2πr (using 3.14 as pi)

so C=2(3.14)(45)

so C=90(3.14)

so C≈282.6 or D

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Solve the inequality x^2-4x-7<0

ANEK [815]

Answer:

Inequality Form:

2 − √ 11 < x < 2 + √ 11

Interval Notation:

( 2 − √ 11 , 2 + √ 11 )

Step-by-step explanation:

Solve the inequality for x by finding a , b , and c of the quadratic then applying the quadratic formula.

8 0

3 years ago

A members-only speaker series allows people to join for $28 and then pay $4 for every event attended. What is the total cost for

wariber [46]

Given:

Joining fee = $28

Fee of each event = $4

To find:

Total cost for someone to attend 4 events.

Solution:

Let the number of events be x and total fee be y.

Fee for 1 event = $4

Fee for x events = $4x

Joining fee remains constant. So, the total fee is

$y=28+4x$

Substitute x=4 in this equation.

$y=28+4(4)$

$y=28+16$

$y=44$

Therefore, total cost of 4 events is $44.

8 0

3 years ago

Last year Chesa made 32 one-cup servings of soup for a school party. This year, she will make two times the amount of soup that

Nezavi [6.7K]

Answer:

Step-by-step explanation:

6 0

3 years ago

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimeters,

tiny-mole [99]

Answer:

Probability that the sample mean would be greater than 141.4 millimetres is 0.3594.

Step-by-step explanation:

We are given that Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimetres, and a standard deviation of 7.

A random sample of 39 steel bolts is selected.

Let $\bar X$ = sample mean diameter

The z score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ ~ N(0,1)

where, $\mu$ = population mean diameter = 141 millimetres

$\sigma$ = standard deviation = 7 millimetres

n = sample of steel bolts = 39

Now, Percentage the sample mean would be greater than 141.4 millimetres is given by = P( $\bar X$ > 141.4 millimetres)

P( $\bar X$ > 141.4) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ > $\frac{141.4-141}{\frac{7}{\sqrt{39} } } }$ ) = P(Z > 0.36) = 1 - P(Z $\leq$ 0.36)

= 1 - 0.6406 = 0.3594

The above probability is calculated by looking at the value of x = 0.36 in the z table which has an area of 0.6406.

8 0

3 years ago

How do u do this? HELPPPPPPPPPPPPPP

givi [52]

Bare with me a minute, I am still trying to figure it out. Here is what I have so far.

6 0

3 years ago