Answer:
The chosen topic is not meant for use with this type of problem. Try the examples below.
|2y| = 3 + 2
− 2 (y+2) = 2 −y
x−2=4
Step-by-step explanation:
Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
I would say (I am abbreviating square root to sqrt)
1. 4 sqrt(8488) = 4 sqrt(2x2x2122) = 8 sqrt(2122)
2. 3 sqrt(6936) = 3 sqrt(6x34x34) = 102 sqrt (6)
3. 2 sqrt(8648) = 2 sqrt(2x2x2162) = 4 sqrt(2162)
Answer:
g = 4
Step-by-step explanation:
5g = 20
Divide each side by 5
5g/5 = 20/5
g = 4
