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Ne4ueva [31]
2 years ago
5

Hello... what is the formula for solving the sides of a right triangle?

Mathematics
2 answers:
Kruka [31]2 years ago
6 0

wait brainly can delete your questions ?

Step-by-step explanation:

tankabanditka [31]2 years ago
6 0

Answer:

You can use the Pythagorean theorem

Step-by-step explanation:

The equation is a^2+b^2=c^2

(the ^ thing indicates an exponent here)

Say you have a right triangle with one side being 5cm, and another being 12cm, you can plug those two values into the equation as such

5^2+12^2=c^2

then you solve

5 to the second power is 25, and 12 to the second power is 144. put those two in and you got

25+144=c^2

add the two

169=c^2

Once you get there, you take the square root of 169(nice) which would get you 13.

And that right there, would be your answer to this problem.

Hope this helps! The equation can go either way too.

You can arrange it like b^2+c^2=a^2 or c^2+a^2=b^2 or whatever you want.

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he is not

Step-by-step explanation:

a whole number has no decimal and it is not a fraction and NO NEGATIVES 3/2is a fraction/decimal so it is not a whole number

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Answer:

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Step-by-step explanation:

f(x) =x^2 - 6x + 21

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3 years ago
A recipe for lemonade calls for 1 cup of sugar and 7 cups of water.how much sugar is used per cup of water
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7 0
3 years ago
insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of
ss7ja [257]

Answer: (13.22\%,\ 19.34\%)

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : \hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628

=16.28\%

Significance level : \alpha= 1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

Confidence level for population proportion:-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= (13.22\%,\ 19.34\%)

7 0
3 years ago
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