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Dimas [21]
2 years ago
12

Plsss help i’ll give brainliest if you give a correct answer

Mathematics
2 answers:
Ugo [173]2 years ago
8 0

Answer:

23

Step-by-step explanation:

wel2 years ago
8 0

Answer:

I'm pretty sure its 23.

Step-by-step explanation:

I subtracted 38 from 15 and got 23. Then I replaced 23 for x.

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Divide. Round to the nearest tenth.<br> 8 divided by 6.403
Thepotemich [5.8K]

Answer:

1.2

Step-by-step explanation:

(I am not a good explainer)

6 0
3 years ago
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Stuck on this question
sashaice [31]

Answer:

9262

Step-by-step explanation:

just plug in 22 for n and calculate

6 0
3 years ago
Select the gcf of these numbers. 25 · 5· 11 and 23· 52 · 7 a 2^2 · 3
White raven [17]
The greatest common factor of the numbers is that which is the fused factors of all the numbers without the repetition of the common factors present in the given.
                          25·5·11 = 5·5·5·11
                          23·52·7 =23·2·2·13·7
Since, there are no repeated factors, the answer would be,
                                        5·5·5·11·23·2·2·13·7
The answer unfortunately is not among the choices.
7 0
3 years ago
The coordinates of trapezoid ABCD are A(−4, 3), B(2, 3), C(4, −1) and D(−4, −1). A line segment runs through the trapezoid with
madam [21]
The distance from point Y to the y-axis is 4 units and the distance from point Z to the y-axis is 3 units, then the lelgth of the segment YZ is 4+3=7 units.
If <span>a scale factor is 3, then the length of Y'Z' will be 7·3=21 units.
</span>
P.S. In the added picture you can see trapezoid ABCD that was dilated by a scale factor 3 about the origin. This may help to understand that all linear values after dilation become multiplied by scale factor.
<span> </span>

5 0
3 years ago
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A pair of ordinary dice is rolled. What is the probability that each die will show a number higher than 4. 1. (1/36) 2. (1/12) 3
mihalych1998 [28]

Answer:

the answer is 1/12

Step-by-step explanation:

it is 1/12 because if there are only a pair you would have 2 dice. and since each die has numbers all the way up to 6 all you have to do is add them. and don't count all the numbers. like add 1+2+3+4+5+6. that's just plain wrong just do add the highest number on each die (6+6)

8 0
3 years ago
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