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ElenaW [278]
3 years ago
5

What is the solution to (2 - 1)(4 - 2) + 9 ?

Mathematics
2 answers:
Sidana [21]3 years ago
7 0
(2-1)(4-2)+9
((1)(2))+9
(2)+9
11
inysia [295]3 years ago
6 0

Answer:

(2 - 1)(4 - 2) + 9

= 11

Step-by-step explanation:

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a positive number is 7 times another number if 3 is added to both the numbers then one of the new number becomes 5 by 2 times th
Neko [114]

Answer:

7 and 1

Step-by-step explanation:

Let the numbers be a and b.

<u>A positive number is 7 times another number:</u>

  • a = 7b

<u>If 3 is added to both the numbers then one of the new number becomes 5 by 2 times the other new number:</u>

  • a+3 = 5/2 × (b +3)

<u>To solve this we substitute </u><u>a</u><u> with </u><u>7b</u><u> in the second equation:</u>

  • 7b + 3 = 5/2 × (b +3)               ⇒ multiplying both sides by 2
  • 14b + 6 = 5b + 15                    ⇒ collecting like terms
  • 14b - 5b = 15 - 6
  • 9b = 9
  • b = 1                                        ⇒ solved for b

<u>Then, finding a:</u>

  • a= 7b
  • a=7*1
  • a= 7                                        ⇒ solved for a

<u>So the numbers are</u> 7 and 1

3 0
3 years ago
If x=6 find the value of x/2
nekit [7.7K]

Answer:

3

Step-by-step explanation:

6/2=3

7 0
3 years ago
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Please help! Will give brainly, 50 points!! I'm stuck with this question!!
Marizza181 [45]

To solve this problem, you must plugin the value g(x) into f(x). This gives you (x-3)^2. When you solve that, it gives you x^2 - 6x + 9.

7 0
3 years ago
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the population of a town increases at the rate of 1% each year today the towns population is 8500 what will the population be in
romanna [79]

Answer:

8934 (8933.58542585)

Step-by-step explanation:

8,500 (population currently) * 1.01 (1 percent) ^ 5 (years) = 8933.58542585 ≅ 8934 people.

4 0
4 years ago
What is the area of circle with a radius of 13 milimeters? use 3.14 for pi
MrRissso [65]

Answer:

530.66 mm²

5.3066 cm²

Step-by-step explanation:

A = π·r²

= 3.14×(13mm)²

= 3.14×169mm²

= 530.66 mm²

= 5.3066 cm²

8 0
3 years ago
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