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REY [17]
3 years ago
13

Name the relationship A.complementary B.linear pair C.vertical D.adjacent

Mathematics
1 answer:
Tom [10]3 years ago
4 0

Answer:

∠a and ∠b are the adjacent angles.

Therefore, option D i.e. adjacent is the correct option.

Step-by-step explanation:

Given the angles

  • ∠a
  • ∠b

We know that the two angles are termed as the adjacent angles when they share the:

  • common vertex
  • common side

From the given diagram, we are given the angles ∠a and ∠b.

It is clear that angles ∠a and ∠b have a common vertex and common side.

Therefore, the relationship between the angles ∠a and ∠b is 'adjacent'.

In other words, ∠a and ∠b are the adjacent angles.

<em />

<u><em>Please note that the given relation can not be a 'linear pair' because the sum of two angles is NOT a straight line or 180°.</em></u>

<u><em /></u>

Therefore, option D i.e. adjacent is the correct option.

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the radius of one circular field is 5m and that of other is 3m.find the radius of circular field whose area is the difference of
Alex777 [14]

Answer:

4m

Step-by-step explanation:

  1. Recall the formula for area of a circle for each calculation
  2. Calculate the area of the large field (r = 5m)
  3. Calculate the area of the small field (r = 3m)
  4. Find the difference in area
  5. Find the radius of the "difference" field using difference in area

The formula for area of a circle is A = πr².

"A" means area.

π is pi. <em>I will use the π button</em>, but some teachers ask to use 3.14.

"r" means radius.

Area of large field:

Substitute "r" for 5m in the formula.

A = πr²

A = π(5m)²

A = π25m²

A = 78.5398163397 m²

Area of small field:

Substitute "r" for 3m in the formula.

A = πr²

A = π(3m)²

A = π9m²

A = 28.2743338823  m²

Difference in areas:

Subtract the area of small field from the area of large field.

(78.5398163397 m²) - (28.2743338823  m²)

= 50.2654825 m²

Radius of "difference" field:

Since we are looking for radius, not area, rearrange the formula to isolate "r".

A = πr²

\frac{A}{\pi } = \frac{\pi r^{2}}{\pi}     Divide both sides by π

\frac{A}{\pi } = r²                π cancels out on the right side

\frac{A}{\pi } = √r²             Square root both sides

\sqrt{\frac{A}{\pi }} = r        ² and √ cancel out, leaving "r" isolated

r = \sqrt{\frac{A}{\pi }}       Variable on the left for standard formatting

Substitute "A" for the difference in area

r = \sqrt{\frac{A}{\pi }}

r = \sqrt{\frac{50.2654825m^{2}}{\pi }}     Divide by pi first

r = \sqrt{16.0000000135&#10;m^{2}}            Find the square root

r ≈ 4m

The radius of the field that has the area of the difference in the two fields is 4m.

3 0
3 years ago
7x - 2 = 2y 3x = 2y - 1
77julia77 [94]
<span>7x - 2 = 2y
7x = 2y + 2
so
</span>7x = 2y + 2<span>
3x = 2y - 1 
----------------subtract
4x = 3
  x = 3/4

</span>7x - 2 = 2y
7(3/4) - 2 = 2y
21/4 - 2 = 2y
21/4 - 8/4 = 2y
13/4 = 2y
so
y = 13/4 * 1/2
y = 13/8

answer
<span>(3/4, 13/8)</span>


4 0
4 years ago
5. Ms. Peregrino is using her cards to call on
Ira Lisetskai [31]

Answer: 2/34

Step-by-step explanation: there are 2 sticks with the same name and the total number of students are 34 so its 2/34

7 0
3 years ago
Can someone explain to me what a “derivative” means? How do you find the derivative of f(x)=x^3+1?
Ostrovityanka [42]
The derivative is the rate of change of a function, basically represents the slope at different points. To find the derivative of the given function you can use the power rule, which means, if n is a real number, d/dx(x^n)= nx^(n-1). This is a simplification of the chain rule based on the fact that d/dx(x)=1. Anyway, this means that d/dx(x^3 + 1)= 3x^2. Here n is 3 and so it is 3*x^(3-1)= 3x^2. The derivative of x^3+1 is 3x^2.

If you are wondering what happened to the 1, for any constant C, d/dx(C)=0.
4 0
3 years ago
Jayden leans a 30-foot ladder against a wall so that it forms an angle of 65 ∘ with the ground. How high up the wall does the la
vaieri [72.5K]

Answer:

27.19 ft.

Step-by-step explanation:

sin 65 = x/30

sin 65(30) = x

27.189 ≈27.19

8 0
3 years ago
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