Answer:
1.
If you can choose more than one answer for #1, a and b are correct.
If you can only choose one, the answer will for sure be b, the nucleus.
2.
d, large central vacuole, cell wall
3.
e. male
4.
b. ss, smooth seeds
5.
b. They both have a cell as their basic unit.
(5, 12) e (-10, -3)
x.......y...1
5.....12..1
-10..-3..1
12x -10y -15 + 120 -5y + 3x = 0
12x + 3x - 10y - 5y - 15 + 120 = 0
15x - 15y + 105 = 0 :(5)
3x - 5y + 21 = 0
m = -a/b
m = -3/-5
m(5) = 3/5
y-yo = m(x-xo)
y-14 = 3/5*(x-7)
y-14 = 3x/5 - 7/5
3x/5 - y + 14 - 7/5 = 0
3x/5 - 5y/5 + 70/5 - 7/5 = 0
3x - 5y + 70 - 7 =0
3x - 5y + 63 = 0
m(s) = -3/-5 = 3/5
m(r) = m(s) --> são paralelas
You will want to start by making your fractions have the same denominator. To do this, multiply the 2/3 by 2/2, to make it 4/6. Now we have this equation:
-4/6x = 1/6x + 4
Next, subtract 1/6x from both sides:
-5/6x = 4
Finally, multiply both sides by -6/5, and you get your answer:
x = -4.8
Answer:
We know that:
There is a total of 81 houses:
51 had a finished basement.
56 had a three-car garage.
37 had a finished basement and a three-car garage.
a) How many had a finished basement but not a three-car garage?
51 had a finished basement, and 37 have a finished basement and the garage, then:
51 - 37 = 14 hoses have only the basement.
b) How many had a three-car garage but not a finished basement?
Same reasoning as above:
56 - 37 = 19 houses only have the garage.
c) How many had either a finished basement or a three-car garage?
Now we only count the ones that have one finished thing, in this case, we already found the number of houses that have only the garage or only the basement, then the number of houses that either had a finished basement or a finished garage is:
19 + 18 = 37 houses.
Answer: w=(P - 2L)/2
Step-by-step explanation:
P=2L+2W
P - 2L=2W
Divide both sides by 2
(P - 2L)/2=2W/2
(P - 2L)/2=W
W=(P - 2L)/2
