Tan²( θ ) - (1 + √3) tan (θ) + √3 = 0

tan²( θ ) - (tan (θ) + √3 tan (θ)) + √3 = 0

tan²( θ ) - tan (θ) - √3 tan (θ) + √3 = 0

tan( θ ) ( tan (θ) - 1) - √3 ( tan (θ) - 1 ) = 0

( tan( θ ) - 1 ) ( tan( θ ) - √3 ) = 0

tan( θ ) - 1 = 0

θ = π/₄

tan( θ ) - √3 = 0

θ = π/₃

so θ = π/₄ and θ = π/₃

7 0

3 years ago

Read 2 more answers

What is the equation in point-slope form of a line that passes through the points (3, −5) and (−8, 4) ?

maxonik [38]

ANSWER

$y + 5= - \frac{9}{11} (x-3)$

or

$y - 4= - \frac{9}{11} (x + 8)$

EXPLANATION

We want to find the equation in point-slope form of a line that passes through the points (3, −5) and (−8, 4).

The point-slope form is given by;

$y-y_1=m(x-x_1)$

where

$m = \frac{4 - - 5}{ - 8 - 3} = \frac{4 + 5}{ - 11} = - \frac{9}{11}$

is the slope of the line.

If

$(x_1,y_1)=(3,-5)$

The point-slope form is

$y + 5= - \frac{9}{11} (x-3)$

On the other hand, if
$(x_1,y_1)=( - 8,4)$

Then the point-slope form is,

$y - 4= - \frac{9}{11} (x + 8)$

These two equations are the same when simplified.

4 0

3 years ago

Simplify the expression:<br> 6x - 4x + 12 - 1

Rus_ich [418]

Answer:

Step-by-step explanation:

$6x - 4x + 12 - 1\\\\$