Sorry it's a bit messy. but I hope you understand and it will help
Good morning Mr. William I wanted to ask you if it is still possible to change an elective class
5x + 9y = 0
to find the x int, sub in 0 for y and solve for x
5x + 9(0) = 0
5x = 0
x = 0
to find the y int, sub in 0 for x and solve for y
5(0) + 9y = 0
9y = 0
y = 0
the reason u cannot use just the intercepts is because the line goes through the origin (0,0)....The intercepts coincide giving u only 1 point...and that is not enough to graph a line
Answer:
all you need to do is to multiple
