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Gekata [30.6K]
2 years ago
15

Eric eats 1/6 of an apple pie and Jack eats 1/4 of the apple pie. How much of the pie has been eaten?

Mathematics
2 answers:
Genrish500 [490]2 years ago
8 0
The answer is C) \frac{7}{12}
sp2606 [1]2 years ago
4 0
It is B) 5/12
Lemme know if you want to know why:)
---
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3 years ago
Can you guys please help me solve this
Delicious77 [7]

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3 years ago
Triangle $ABC$ has a right angle at $B$. Legs $\overline{AB}$ and $\overline{CB}$ are extended past point $B$ to points $D$ and
Lisa [10]

Answer:

Given :

ABC is a right triangle in which ∠ABC = 90°,

Also, Legs AB and CB are extended past point B to points D and E,

Such that,

\angle EAC = \angle ACD = 90^{\circ}

To prove :

EB\times BD=AB\times BC

Proof :

In triangles AEC and EBA,

∠EAC= ∠ABE ( right angles )

∠CEA = ∠AEB ( common angles )

By AA similarity postulate,

\triangle AEC \sim \triangle EBA,

Similarly,

\triangle AEC \sim \triangle ABC

\implies\triangle EBA\sim \triangle ABC-----(1)

Now, In triangles ADC and CBD,

∠ACD = ∠CBD ( right angles )

∠ADC= ∠BDC ( common angles )

By AA similarity postulate,

\triangle ADC \sim \triangle CBD,

Similarly,

\triangle ADC \sim \triangle ABC

\implies \triangle CBD\sim \triangle ABC-----(2)

From equations (1) and (2),

\triangle EBA\sim \triangle CBD

The corresponding sides of similar triangles are in same proportion,

\frac{EB}{BC}=\frac{AB}{BD}

\implies EB\times BD=AB\times BC

Hence, proved....

5 0
2 years ago
Explain why the 25 is rational and the square root of 26 is irrational
torisob [31]

Step-by-step explanation:

rational expression can be written as a ratio and all neutral numbers xan be written as a ratio

root of 26 is irrational because it can't be written as a ratio since its not a whole number.

6 0
3 years ago
observe as seguintes situações e sua representação em linguagem matematica dois numeros x e y são tais 2x y=6 x-y=3
agasfer [191]

Answer:

The value of x any y are "-5.29 and 0.79" and "3.79 and -2.29"

Step-by-step explanation:

Given values:

2xy =6.....(a)\\\\x-y= 3.....(b)\\\\

After solve equation (a) we get

\ equation: \\\\2xy= 6\\\\xy =\frac{6}{2} \\\\xy = 3.....(x)\\\\

After solve equation (b) we get

\ equation: \\\\x-y =3\\\\x= 3+y....(x1)\\

put the value of x in to equation (x)

(3+y)y = 3\\

y^2+3y-3=0\\\\\ compare \ the \ value \ with \ ay^2+by+c=0\\a= 1\\b=3\\c=-3\\\ Formula: \\y= \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\y= \frac{-3\pm \sqrt{9+12}}{2}\\y= \frac{-3\pm \sqrt{21}}{2}\\

The value of y is = -5.29 and 0.79, put the value of y in x1 equation so, we get: 3.79 and -2.29

5 0
3 years ago
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