I need some help with this, can someone help me?

Jerry is planting white daisies and red tulips in his garden and he wants to choose a pattern in which the tulips surround the d

andre [41]

The borders are shown in the picture attached.

As you can see, starting with border 1, we have 6 daises (white squares) surrounded by 10 tulips (colored squares). Through Jerry's expression we expected:
8(b − 1) + 10 =
8(1 − 1) + 10 =
0 + 10 =
10 tulips.

When considering border 2, we expect:
8(b − 1) + 10 =
8(2 − 1) + 10 =
8 + 10 =
18 tulips.
Indeed, we have the 10 tulips from border 1 and 8 additional tulips, for a total of 18 tulips.

Then, consider border 3, we expect:
8(b − 1) + 10 =
8(3 − 1) + 10 =
16 + 10 =
26 tulips.
Again, this is correct: we have the 10 tulips used in border 1 plus other 16 tulips, for a total of 26.

Therefore, Jerry's expression is correct.

6 0

3 years ago

QUESTION 3 - Distinguish whether the following pairs of events are dependent

TiliK225 [7]

Two eventis are independent if knowledge about the first doesn't change your expectation about the second.

a) Independent: After you know that the first die showed 4, you stille expect all 6 numbers from the second. So, the fact that the first die showed 4 doesn't change your expectation about the second die: it can still show numbers from 1 to 6 with probability 1/6 each.

b) Independent: It's just the same as before. After you know that the first coin landed on heads, you still expect the second coin to land on heads or tails with probability 1/2 each. Knowledge about the first coin changed nothing about your expectation about the second coin.

a) Dependent: In this case, there is a cause-effect relation, so the events are dependent: knowing that a person is short-sighted makes you almost sure that he/she will wear glasses. So, knowledge about being short sighted changed your expectation about wearing glasses.

8 0

3 years ago

In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and

Umnica [9.8K]

Answer:

41

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

A little more detail

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0

3 years ago

Use the graph that shows the solution to

Inessa05 [86]

Answer:

Step-by-step explanation:

c

6 0

3 years ago

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Anit [1.1K]

Well the area of a trapezoid is defined by the following formula:
A = $\frac{1}{2}(b_{1} + b_{2})h$ where b₁ and b₂ are the bases of the trapezoid and h is the height of the trapezoid.

Let's plug in what we know into this formula:
h = 7 the perpendicular distance between the two bases
b₁ = 15 the shorter parallel side
b₂ = 25 the longer parallel side made up of 4 + 15 + 6
so, A = $\frac{1}{2} (15+25)(7)=140$

This is in square units of measure of course, so 140 in²

8 0

3 years ago