Answer:
since I can't see the whole shape or what the question is asking for, I'm going to assume that the shape is a square and that the question is asking for the perimeter because that appears to be the only way to get 6x–2

Step-by-step explanation:
to get the answer 6x–2, you would have to multiply the base by 2 and the height by 2 and add them together.
Make proportions and reduce them.
6/9=2/3
10/15=2/3
The two rectangles are similar proportionally with a ratio of 2:3.
Does that answer your question?
Answer:
The wind pushed the plane
miles in the direction of
East of North with respect to the destination point.
Step-by-step explanation:
Let origin, O, br the starting point and point D be the destination at 250 miles at a bearing of 20° E of S, but due to wind let D' be the actual position of the plane at 230 miles away from the starting point in the direction of 35° E of South as shown in the figure.
So, we have |OD|=250 miles and |OD'|=230 miles.
Vector
is the displacement vector of the plane pushed by the wind.
From figure, the magnitude of the required displacement vector is

and the direction is
east of north as shown in the figure,

From the figure,



miles
Again, 


miles
Now, from equations (i) and (ii), we have
miles, and


Hence, the wind pushed the plane
miles in the direction of
E astof North with respect to the destination point.
Answer:

Step-by-step explanation:
<u>Modeling With Functions
</u>
We have a table of values of speeds vs distance taken for a car to stop. We are required to find a model that uses the square root and fits the given data to predict other values of d as a function of v.
By the nature of the problem, we can know that for v=0, d must be 0 too. So our model won't include a vertical shift or independent term. Being v the speed of the car and x the distance it takes to stop, we use the following model

We must find A to make the function fit the data. Let's use the first point (v,x); (20,9)

Solving for A


Then we have

Evaluating for v=35


Last option
Step-by-step explanation: it's answer is 8
hope it is helpful to you