All categories

3 years ago

The earth revolves around the sun therefore

1 answer:

8 0

C) (esther?) The orbal velocity is constant.

If it weren't constant, we wouldn't be revolving around the sun at all times, would we? :)

You might be interested in

Hello hello I need help asap

irina1246 [14]

13/4 and 3 1/4
Hope this helps

5 0

3 years ago

Read 2 more answers

Every Thursday, Matt and Dave's Video Venture has “roll-the-dice" day. A customer may choose to roll two fair dice and rent a se

shepuryov [24]

Using the normal distribution, it is found that there is a 0.1357 = 13.57% probability that the total amount paid for these second movies will exceed $15.00.

In a <em>normal distribution</em> with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

For n instances of a normal variable, the mean is $n\mu$ and the standard error is $s = \sigma\sqrt{n}$

In this problem:

Mean of $0.47, standard deviation $0.15, hence $\mu = 0.47, \sigma = 0.15$

30 instances, hence $n\mu = 30(0.47) = 14.1, s = 0.15\sqrt{30} = 0.8216$

The probability is <u>1 subtracted by the p-value of Z when X = 15</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

Considering the n instances:

$Z = \frac{X - n\mu}{s}$

$Z = \frac{15 - 14.1}{0.8216}$

$Z = 1.1$

$Z = 1.1$ has a p-value of 0.8643.

1 - 0.8643 = 0.1357.

0.1357 = 13.57% probability that the total amount paid for these second movies will exceed $15.00.

A similar problem is given at brainly.com/question/25769446

6 0

2 years ago

Shelley just got a weekly allowance of $15. She uses her allowance to buy a pencil bag for

Licemer1 [7]

Answer:

6 dollars

Step-by-step explanation:

15-6=9

9-3=6

8 0

3 years ago

Read 2 more answers

Which of the following sets represents a function?

Llana [10]

Step-by-step Answer:

Whenever two relations that has identical values in the independent variable, i.e. x, or the first variable, but having a different value for the dependent variable, it is NOT a function.

For example, {(5,4),(5,6),(2,3)} is NOT a function because the identical values of the independent variable "5" do not correspond to the same value of the dependent variable.

In other words, when we are given an input of 5, we do not know if the output is 4 or 6, so it is NOT a function.

If the output is defined whenever we are given a valid input, it is a function.

For the given examples,

{(3,5),(-1,7),(3,9)} => NOT a function because when given an input of "3", we cannot determine output.

{(1,2),(3,2),(5,7)} => IS a function, because when we are given any of the valid inputs (1, 3, or 5), we have a unique output.

Similarly the first one,

{(1,2),(1,4),(1,6)} => NOT a function, because we cannot determine a unique output when given an input of "1".

5 0

3 years ago

30;34 in simplest form

Natalka [10]

The fraction 30/34 is equivalent to 15/17.

3 0

3 years ago