Answer:
26.4 is what i came up with if you divide im probably wrong sorry if i am
Answer:
See below.
Step-by-step explanation:
Fifth root of 243 = 3,
Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),
then r^5( cos Ф + i sin Ф )^5 = 243(cos 240 + i sin 240).
Equating equal parts and using de Moivre's theorem:
r^5 =243 and cos 5Ф + i sin 5Ф = cos 240 + i sin 240
r = 3 and 5Ф = 240 +360p so Ф = 48 + 72p
So Ф = 48, 120, 192, 264, 336 for 48 ≤ Ф < 360
So there are 5 distinct solutions given by:
3(cos 48 + i sin 48),
3(cos 120 + i sin 120),
3(cos 192 + i sin 192),
3(cos 264 + i sin 264),
3(cos 336 + i sin 336).. (Answer).
Answer:
D
Step-by-step explanation:
To find the intercepts, that is where the line crosses the x and y axes
• Let x = 0, in the equation for y-intercept
• Let y = 0, in the equation for x- intercept
x = 0 : - 3y = - 9 ⇒ y = 3 ⇒ (0, 3) ← y- intercept
y = 0 : x = - 9 ⇒ (- 9, 0 )← x- intercept
Answer:
m∠RST = 155°
m∠RSU = 102°
Step-by-step explanation:
m∠RST = m∠RSU + m∠UST
12x - 1 = 9x - 15 + 53
12x - 9x = 1- 15 + 53
3x = 39
x = 39/3
x = 13°
m∠RST = (12x -1)° = (12 * 13 - 1)° = (156 - 1 )° = 155°
m∠RSU = (9x -15)° = (9 * 13 - 15)° = ( 117 - 15)° = 102°
