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3 years ago

12

The interest on an investment varies directly as the rate of interest. If the interest is $43 when the interest rate is 5%, fi

nd the interest when the rate is 6.6%.

1 answer:

Alenkasestr [34]3 years ago

5 0

The answer is $43 * 6.6% = 2.838

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Socket set for $36.00 with 40% off plus 8.25 % sales tax. How much do I owe?

OlgaM077 [116]

whatever% of anything is just (whatever/100) * anything.

so the socket set has a 40% off, what is 40% of 36? well, is just (40/100) * 36, or 14.4, that's the discount, so the sale price is 36 - 14.4, or 21.6.

plus the 8.25% taxation, what is 8.25% of 21.6? well, is just (8.25/100) * 21.6, or 1.782.

so the total price is 21.6 + 1.782, or 23.382, or about 23 bucks and 38 cents.

3 0

3 years ago

Read 2 more answers

a glass of jar contains 1 red, 3 green and 2 blue marbles. asingle marble is chosen at random from the jar and its color is reco

lubasha [3.4K]

hi,

first let's count the marbles : 1+3+2 = 6

so picking a red is 1/6

a green is : 3/6

a bleu is : 2/6

4 0

3 years ago

A rectangle on a coordinate plane has vertices (-1.1), R(6, 1). S(6.-8), and T(-1,-8). What are the dimensions of the

Monica [59]

Answer:

b. the base is 9 and the height is 6

Step-by-step explanation:

6 0

2 years ago

A family purchased basketball tickets online. The total cost, c, in dollars, of t tickets can be found using the function below.

Reptile [31]

Solution:
C=32.50t+8.50
236=32.50t+8.50
236-8.50=32.50t
227.50=32.50t
227.50/32.50=32.50t/32.50
t=7

The family bought 7 tickets.

3 0

3 years ago

A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled

klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}$

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

$\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5$

The standard deviation of the sample is calculated as:

$s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8$

Then, we can calculate the standard error of the mean as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5$

6 0

3 years ago