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dlinn [17]
3 years ago
12

Solve the following system of equations: x − 2y = 5 2x − 4y = 10

Mathematics
1 answer:
emmasim [6.3K]3 years ago
5 0
\left\{\begin{array}{ccc}x-2y=5\\2x-4y=10&|divide\ both\ sides\ by\ (-2)\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}x-2y=5\\-x+2y=-5\end{array}\right}\\.\ \ \ \ \ \ \ \ \ \ \ 0=0-true\\\\Answer:infinitely\ many\ solutions\    \left\{\begin{array}{ccc}x\in\mathbb{R}\\y=\dfrac{x-5}{2}\end{array}\right
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Let g(x) = 3x + 2. If g(x) = 11, what is x?
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3=x

Step-by-step explanation:

11=3x+2

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Which graph represents the function f(x) = 1/3 |x|
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Step-by-step explanation:

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In a recent poll, 778 adults were asked to identify their favorite seat when they fly, and 492 of them chose a window seat. Use
seropon [69]

Answer:

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

p_v =P(Z>7.36)=9.19x10^{-14}  

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

Step-by-step explanation:

1) Data given and notation

n=778 represent the random sample taken

X=492 represent the people that chose a window seat.

\hat p=\frac{492}{778}=0.632 estimated proportion of people that chose a window seat.

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the majority of adults prefer window seats when they fly:  

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.632 -0.5}{\sqrt{\frac{0.5(1-0.5)}{778}}}=7.36  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>7.36)=9.19x10^{-14}  

5) Conclusion

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

6 0
3 years ago
Answer choices are <br> A)50<br> B)55<br> C)100<br> D)110
Olegator [25]
Answer: 50 degrees

You cut the arc measure 100 degrees in half. This is using the inscribed angle theorem. The angle 'a' is the inscribed angle that cuts off this 100 degree arc.
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