Can someone help with these 3 im stuck:((((((((

Find the slope of the line that would pass

Leno4ka [110]

Answer:

10

Step-by-step explanation:

Here we go!

Slope Formula:

$\frac{ {y}^{2} - {y}^{1} }{ {x}^{2} - {x}^{1} }$

What we know: (-4, -52) and (-1, -22)

Plug in the numbers!

$\frac{ - 52 - ( - 22)}{ - 4 - ( - 1)}$

Fix it!

$\frac{ - 52 + 22}{ - 4 + 1}$

Add

$\frac{ - 30}{ - 3}$

Divide

(negative divided by a negative is a positive!!)

Slope is 10

Hope this helps!

4 0

3 years ago

Ariana started a savings account with $240. She deposits $30 into her account at the end of each month. She wants to know how ma

mafiozo [28]

Answer:

9 months

Step-by-step explanation:

$500 - $240 = $260

$260/$30 = 8.67(3s.f.) ≈ 9 months

Recheck:

Balance after 9 months = 240 + (30×9) = 240 + 270 = $510

∴ $510 > $500

8 0

3 years ago

Please answer these two questions

LUCKY_DIMON [66]

It’s better to have a low score and for the second one thumber I think....

3 0

3 years ago

URGENT!!!

rusak2 [61]

Answer:

Step-by-step explanation:

First, the acceleration of gravity is -9.8m/s^2. This still works out since the formula uses 1/2 of it.

Hopefully you see where the other parts come from. Anyway, standard form of a quadratic is ax^2+bx+c=0. So this is almost there. You just need to subtract that 2.1 from both sides.

-4.9t^2+7.5t+-.3=0

Now with this, since it has taken into account the height that the ball was caught with that 2.1, you just need to find the 0s, which is what the quadratic equation does.

The quadratic equation is (-b±sqrt(b^2-4ac))/(2a) and we have a = -4.9, b = 7.5 and c = -.3. Remember you want to keep the signs. Now we just plug in.

(-b±sqrt(b^2-4ac))/(2a)

(-7.5±sqrt((-7.5)^2-4*-4.9*-.3))/(2*-4.9)

(-7.5±sqrt(56.25-5.88))/(.9.8)

(-7.5±sqrt(50.37))/(-9.8)

(-7.5±7.097)/(-9.8)

The plus or minus means there are two equations.

(-7.5+7.097)/(-9.8) and (-7.5-7.097)/(-9.8) So we will solve for both of these.

.04112 and 1.4895. That means these two times are when the ball is at 2.1 meters. One time on the way up and one time on the way down. We can safely assume that the other player catches the ball on the way down, so we want to use the second time, so 1.4895 seconds.

4 0

4 years ago

PLEASE HELP FAST I NEED A EXPERT OR HIGHER 20 POINTS! I need the domain and range of each Graph 2 number so for example 5/1 or s

Andrews [41]

Problem 1

Answers:

Domain: $-3 \le x < 5$

Range: $-4 < y \le 3$

--------------------

Explanation:

The domain is the set of allowed x inputs of a function. The smallest x value we can use is x = -3 (note the very left-most point of the graph). The right-most point involves x = 5, but we can't actually use this x value due to the open hole. So that's why we don't have "or equal to" attached to the 5.

The range is the set of possible y outputs. The lowest we can go is y = -4, but we don't include this as part of the range. The largest y can get is y = 3. So the range is $-4 < y \le 3$

===========================================

Problem 2

Answers:

Domain: $-2 < x < 4$

Range: $-2 < y < 5$

--------------------

Explanation:

We use the same idea as in problem 1. Both endpoints are open holes, so we don't include them as part of the domain and range. For instance, we can't include x = 4 but we can get closer and closer to it. The same idea applies to the range as well.

===========================================

Problem 3

Answers:

Domain: $1 \le x \le 4$

Range: $-4 \le y \le -1$

--------------------

Explanation:

The same idea applies as used earlier. This time we include both endpoints, so we have "or equal to" as part of each inequality sign.

5 0

3 years ago