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Rina8888 [55]
2 years ago
11

I need help with this problem.

Mathematics
1 answer:
Phantasy [73]2 years ago
6 0
Csc^2x-cot^2x=1

Here is why

csc^2x=1+cot^2x

so:
1+cot^2x-cot^2x=1
1=1

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If x is 12% of 180, then what is the value of 7x ?
GuDViN [60]

Answer:

7uby-step explanation:

8 0
3 years ago
Please help :( Im desperate
ki77a [65]

Answer:

(2,4)

Step-by-step explanation:

When graphed the lines intersect at point (2,4) which is the solution.

8 0
2 years ago
A line goes through the origin and the point (6, 14). The point (2, y) is also on the line. Calculate y and justify that your va
guajiro [1.7K]

Answer:

Step-by-step explanation:

The key here is knowing that the equation of the line that passes through these points is same

Thus having (6,14) and (0,0), the slope is as follows;

m = y2-y1/x2-x1 = 0-14/0-6 = -14/-6 = 7/3

Now we can use this slope here to get the value of y in the question

All we need to do is tie write the equation of the line for between the points (6,14) and (2,y)

That would be;

7/3 = y-14/1-6

7/3 = y-14/-5

cross multiply;

-35 = 3(y-14)

-35 = -3y + 42

-3y = -35-42

-3y= -77

y = -77/3

y = 77/3

3 0
3 years ago
shira was riding the screamer when it broke down. her seat was 53 jorizontal feet from the central support pole. What was her se
ki77a [65]

Answer:

The possible solutions are 58 degree, 122 degrees, 302 degrees and 238 degrees

Step-by-step explanation:

Please see the attachment

From the figure, it is evident that

cos AOB = OB/OA = 53/100 = 0.53

Thus, cos-1 (0.53) = 58 degrees

AOB = 58 degree

Also, there are can be other values depending on the quadrants

COB = 180 -58 = 122 degrees

FOB = 360 -58 = 302 degrees

EOB = 180 + 58 = 238 degrees

5 0
3 years ago
two-fifth of the students in a mixed school are boys. if there are 30 girl in the school how many are boys​
lilavasa [31]
12. 1/5 of 30 = 6. 6 x 2 = 12
6 0
3 years ago
Read 2 more answers
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