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2 years ago

I need help with this problem.

Mathematics

1 answer:

Phantasy [73]2 years ago

6 0

Csc^2x-cot^2x=1

Here is why

csc^2x=1+cot^2x

so:
1+cot^2x-cot^2x=1
1=1

You might be interested in

(7x2) x 3

Sindrei [870]

First you need to multiply the one in the bracket 7x2 which is 14 then u must multiply it with 3 to get the answer so 14x3 which equals to 42

7 0

1 year ago

Determine side x. Round to the nearest unit. 20 9 12 5

tatyana61 [14]

Answer:

Step-by-step explanation:

First, you will have to use trigonometry. Since the side of the triangleis the opposite of the angle 53 and the hypotenuse, you will use sin.

Sin 53 degrees = opposite side / hypotenuse side.

The opposite side is x and the hypotenuse side equals 15.

sin53= x/15

15 ( sin 53 ) =x

x= 11.97953

Round

x=12

6 0

2 years ago

245. 202, 254, 245, 276 Write the values from least to greatest Mean Median: Mode:

Burka [1]

Answer:

The values from least to greatest would be 202, 245, 245, 254, 276

The mean would be 244.4

The median would be 245

The mode would be 245

Step-by-step explanation:

To find the mean, you add all the numbers together and divide that sum by the number of numbers. In this case, you add all the numbers together and you get 1222. Next, you divide that by 5 because there are 5 numbers. To find the median, you order the numbers from least to greatest and find the middle number. For this question, the answer would be 245. Lastly, to find the mode you look for the number that appears the most. In this case it's 245.

7 0

3 years ago

Your friend says that the absolute value equation |3x+8|−9=−5 has no solution because the constant on the right side of the equa

xenn [34]

$Solution, solve\:for\:x,\:\left|3x+8\right|-9=-5\quad :\quad x=-4\quad \mathrm{or}\quad \:x=-\frac{4}{3}$

$Steps:$

$\left|3x+8\right|-9=-5$

$\mathrm{Add\:}9\mathrm{\:to\:both\:sides},\\\left|3x+8\right|-9+9=-5+9$

$\mathrm{Simplify},\\\left|3x+8\right|=4$

$|f\left(x\right)|=a\quad \Rightarrow \:f\left(x\right)=-a\quad \mathrm{or}\quad \:f\left(x\right)=a,\\3x+8=-4\quad \quad \mathrm{or}\quad \:\quad \:3x+8=4$

$3x+8=-4,\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides},\\3x+8-8=-4-8,\\\mathrm{Simplify},\\3x=-12,\\\mathrm{Divide\:both\:sides\:by\:}3,\\\frac{3x}{3}=\frac{-12}{3},\\\mathrm{Simplify},\\x=-4$

$3x+8=4,\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides},\\3x+8-8=4-8,\\\mathrm{Simplify},\\3x=-4,\\\mathrm{Divide\:both\:sides\:by\:}3,\\\frac{3x}{3}=\frac{-4}{3},\\\mathrm{Simplify},\\x=-\frac{4}{3}$