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jarptica [38.1K]
3 years ago
5

AMP-PNP is a non-hydrolyzable analog of ATP that can bind to proteins in a similar manner as ATP but is no longer hydrolyzed. Pr

edict what would happen to helicase activity if AMP-PNP were added to a DNA replication reaction. Choose one: A. Helicase would function normally, since AMP-PNP is not the same as ATP and would not bind to helicase. B. Helicase would function normally, since AMP-PNP is an analog of ATP and would function in the place of ATP. C. Helicase would function faster than normal, since the AMP-PNP is not hydrolyzed. ATP binding induces conformational changes, but hydrolysis slows DNA unwinding by helicase. D. Helicase would no longer function, since the AMP-PNP is not hydrolyzed. ATP binding and hydrolysis induce the conformational changes that facilitate DNA unwinding by helicase.
Biology
1 answer:
erik [133]3 years ago
6 0

Answer:

The correct answer is - D. Helicase would no longer function, since the AMP-PNP is not hydrolyzed. ATP binding and hydrolysis induce the conformational changes that facilitate DNA unwinding by helicase.

Explanation:

During the replication process, helicase unzips or unwinds the double-stranded DNA. Helicase is a motor protein that uses ATP molecule hydrolysis in order to break the H-bonding between the strands of DNA.

If AMP-PNP added during DNA replication then it will bind to helicase and remains bound to helicase due to fact that it is a nonhydrolyzable ATP analog.

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3 years ago
Find the heat released in cooling 10g of water at 100C down to 25C​
Reika [66]

]To calculate the amount of heat entering or leaving a system, the equation  

Q

=

m

c

Δ

T

is used.

Explanation:

m = mass (in grams)

c = specific heat capacity (J/g°C)

ΔT = change in temperature (°C)

Here, we will use the specific heat capacity for liquid water which is 4.19 J/g°C.

The mass given is 25.0 grams.

As for the change in temperature, I will assume that it start off at room temperature, 25°C.

25

°

C

−

0

°

C

=

25

°

C

Q

=

m

c

Δ

T

Q

=

25

g

r

a

m

s

⋅

4.19

J

g

°

C

⋅

25

°

C

Q

=

2618.75

J

Take into account significant figures and the answer should be

2.6

⋅

10

3

J

Answer link

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vampirchik [111]

Answer: the correct answer is a. 1, 3, 5, 6, 7  

Explanation:

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