I believe that’s false, because for every x there should only be one y, and x(5) has two y’s (1 and 3)
We have,
t = 6.21 s
s = 111 m
u = 0 m/s
To determine: "a" of the particle.
We know,
s = ut + ½ at²
⇒ s = ½ at²
⇒ a = 2s/t²
⇒ a = [2(111 m)]/(6.21 s)²
⇒ a = (222 m)/(38.5641 s²)
⇒ a ≈ 5.75 m/s²
Answer:
f(-8) = 169
Step-by-step explanation:

this is because when 40 is broken down into two numbers (one divisible to get out of the square root, and one not) you get 25 + 15 under the square root. we know that the square root of 25 is 5, so we can put 5 outside the root and leave 15 inside.
-------------- try the next problem, and if you don't understand, please reply back.
answer is for a) 