How many times heavier is a 8 1/4 pound fish than a 6 7/8 pound fish
1 answer:
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Part A:
Let the width of the rectangle be = x inches
As given, the length of a rectangle is 3 more inches than the width so let the length of the rectangle be = x+3 inches
Perimeter is given as = 54 inches
Perimeter =
Equation becomes:
=54
Part B:
Solving the equation we get
Hence, the width of the rectangle is 12 inches
Length = x+3 = 12+3 = 15 inches
Hence, length of the rectangle is 15 inches.
Now, for z to be an integer, the sum x+y must be a divisor of 10.
It has to be a positive divisor since z≥0. Also x≠y.
x≥0 and y≥0 so y can be equal to either 0 or 1. There are 2 solution in this case.
In this case, y can be equal to 0,1, or 2, but for y=1 ⇒ x=1, so there are two solutions.
y can be 0,1,2,3,4 or 5 - 6 solutions
y can be 0,1,2,3,4,5,6,7,8,9,10, but for y=5 ⇒ x=5, so 10 solutions.
2+2+6+10=20 solutions in total.