Answer:
no
Step-by-step explanation:
the sides do not have the same measurments which is required of the SSS postulate
Answer:
The actual SAT-M score marking the 98th percentile is 735.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Find the actual SAT-M score marking the 98th percentile
This is X when Z has a pvalue of 0.98. So it is X when Z = 2.054. So
Answer:
![f^{-1}(x)=\sqrt[3]{x}-6](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-6)
Step-by-step explanation:
![\sqrt[3]{x}=y+6](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3Dy%2B6)
![\sqrt[3]{x}-6=y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D-6%3Dy)
Cost per ticket for the rides = $1.50.
a) Let us assume the number of ride tickets = x.
Total cost of x number of rides = y.
Total amount spent = $48.75.
Amount spent on 20 tickets = 20 × 1.50 = $30
<em>Fair admission charge = Total amount spent - Amount spent on 20 tickets</em>
<em> = $48.75 - $30 = $18.75.</em>
Let us apply slope-intercept form y=mx+b to get the equation.
Total cost of x number of tickets at the rate $1.50 each ticket = 1.50x.
To<em>tal cost of fair = Total cost of x number of tickets + Fair admission charge.</em>
<h3>b) y = 1.50x + 18.75.</h3>
Answer:
3 ft, 5ft, 6ft
Step-by-step explanation:
To build a kennel of my dog, I would try to make it the largest possible with what I have.
So, I would go with the 3 longest planks: 3ft, 5ft and 6ft.
By looking at the length, I see I could make something very close to a right triangle since I could use the 6ft as an hypotenuse, and have the two other sides as 3ft and 5 ft (6² is almost 3²+5², which equal 34).
That means my corner angle would be slightly over 90 degrees.
