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3 years ago

Which of the following steps were applied to ABCD to obtain A'B'C'D'?

Mathematics

1 answer:

meriva3 years ago

4 0

Answer:

It is C because on 12 I can see 3.

Step-by-step explanation:

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Covert 3.92 into a mixed number in simplest form?

12345 [234]

3.92

= 1.00 + 1.00 + 1.00 + 0.92

= 100/100 + 100/100 + 100/100 + 92/100

= 300/100 + 92/100

= 392/100

-------------------------------------------------------

392/100 = 196/50 = 98/25

3 0

3 years ago

Read 2 more answers

If a barber is capable of cutting the hair of 35 people per day and he works 7 days per week, how many haircuts could he give du

Pavel [41]

June=1,225
April=1,225
May=1,225

All June April and May is 3,675 haircuts

6 0

3 years ago

Add 7 plus 8, then add a to the result. Write an expression for the sequence of operations described.

Ipatiy [6.2K]

Answer:

(7 + 8) + a is your answer

4 0

3 years ago

Automobile license plates in Massachusetts usually consist of three digits followed by three letters. The first digit is never z

Serga [27]

Answer:

1,58,18,400

Step-by-step explanation:

1st digit can have the values 1-9 (9 distinct values)

2nd digit can have the values 0-9 (10 distinct values)

3rd digit can have the values 0-9 (10 distinct values)

1st letter can have the value A-Z (26 distinct values)

2nd letter can have the value A-Z (26 distinct values)

3rd letter can have the value A-Z (26 distinct values)

Total number of different plates possible = 9*10*10*26*26*26

=1,58,18,400

3 0

3 years ago

A purchaser of electric relays buys from two suppliers, A and B. Supplier A supplies two of every three relays used by the compa

inessss [21]

Answer:

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409.

Step-by-step explanation:

We can model this question with a binomial distribution random variable.

The sample size is n=60.

The probability that the relay come from supplier A is p=2/3 for any relay.

If we use a normal aproximation, we have the mean and standard deviation:

$\mu=np=60*(2/3)=40\\\\\sigma=\sqrt{npq}=\sqrt{60*(2/3)*(1/3)} =3.65$

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409:

$P(X\leq38)=P(X$

5 0

3 years ago