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melamori03 [73]
3 years ago
8

Calories consumed by members of a track team the day before a race are normally distributed, with a mean of 1,800 calories and a

standard deviation of 100 calories. If a normal curve is sketched using these data, what is the range for 3 standard deviations to the right and to the left of the mean?
0–3,600

1,700–1,900

1,600–2,000

1,500–2,100

_____________________________

The answer is 1,500–2,100

How to find this:

The mean is 1800
The standard deviation is 100

(Subtract 100 from the mean 3 times)
1800 - 100 = 1700
1700 - 100 = 1600
1600 - 100 = 1500

(Add 100 to the mean 3 times)
1800 + 100 = 1900
1900 + 100 = 2000
2000 + 100 = 2100

(The answers are your range)
1500 - 2100

_______________
I just took the test, hope this helps!
Mathematics
1 answer:
irina1246 [14]3 years ago
5 0

Answer: I need help too

Step-by-step explanation:

someone help

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We can solve this problem by using the distance formula. The distance formula is: \sqrt{(x_{1}-x)^{2} + (y_{1} - y)^{2}} We can now put in values and solve.

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3 years ago
***PLEASE HELP***
Molodets [167]
Given:
250 sheep in a 40-acre pasture.
Number of sheep grazing in each acre.

250/40 = 6.25 or 6 sheep per acre

n = 6
sample proportion: signified by ρ
Sample 1: 4 → 4/6 = 0.67
Sample 2: 1 → 1/6 = 0.17
Sample 3: 9 → 9/6 = 1.50

multiply the sample proportion by 1-ρ
Sample 1: 0.67(1-0.67) = 0.67(0.33) = 0.2211
Sample 2: 0.17(1-0.17) = 0.17(0.83) = 0.1411
Sample 3: 1.50(1-1.5) = 1.5(-0.5) = -0.75

divide the result by n. n = 6
Sample 1: 0.2211/6 = 0.03685
Sample 2: 0.1411/6 = 0.02352
Sample 3: -0.75/6 = -0.125

square root of the quotient to get the standard error.
Sample 1: √0.03685 = 0.1919
Sample 2: √0.02352 = 0.1534
Sample 3: √-0.125 = invalid

z value 95% confidence 1.96.

Sample 1: 1.96 * 0.1919 = 0.3761 or 37.61% margin of error
Sample 2: 1.96 * 0.1534 = 0.3007 or 30.07% margin of error


8 0
3 years ago
Need your help ASAP please help
eduard

His average is 86 so it is below 90.  to get his average i just added all of his grades up to get 517 and then I divided 517 by 6 because thats how many grades he has and I got 86.

On the Grade row in the table it would go 83, 94, 79, 90, 96, 75 in order

The Above/Below 90 row would go -7, 4, 11, 7, -6, -3 in order

Lamont needs to get a 99 on his next test to have an average of exactly 90.


I HOPE THIS HELPED! PLEASE RATE ME AND MAKE MY ANSWER MOST BRAINLIEST!!

5 0
3 years ago
Answers and the work for them please
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