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olga55 [171]
2 years ago
9

Anyone know this tell me

Mathematics
2 answers:
d1i1m1o1n [39]2 years ago
4 0

Answer:

Option b

Step-by-step explanation:

Points (2, 3) and (0, 1)

  • y=x+1, x<2

point (2,4)

  • y=x+2, x≥2

These are covered in option b.

Dennis_Churaev [7]2 years ago
4 0
The answer is option b !
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If a varies jointly as b and c,
Alborosie

Given:

a varies jointly as b and c.

a=6 when b=2 and a=3.

To find:

The variation constant and the equation of variation.

Solution:

a varies jointly as b and c.

a\propto bc

a=kbc              ...(i)

Where, k is the constant of proportionality.

a=6 when b=2 and a=3.

6=k(2)(3)

6=6k

\dfrac{6}{6}=k

1=k

The value of k is 1.

Putting k=1 in (i), we get

w=1xy

w=xy

Therefore, the variation constant is 1 and the equation of variation is w=xy.

4 0
2 years ago
The length of a rectangle is 5 m greater than the width. The perimeter is 150 m. find the width
Elza [17]

P = perimeter

Perimeter of a rectangle = l + l + w + w

or  P = 2l + 2w

You know:

P = 150 m

l = w + 5     [length is 5 m greater than the width]

P = 2l + 2w        Plug in what you know

150 = 2(w + 5) + 2w     Simplify, distribute/multiply 2 into (w + 5)

150 = 2w + 10 + 2w

150 = 4w + 10     Subtract 10 to both sides of the equation

140 = 4w       Divide 4 on both sides

35 = w

PROOF               l = w + 5 --->  l = 40

P = 2l + 2w

150 = 2(40) + 2(35)

150 = 80 + 70

150 = 150

4 0
3 years ago
Divide (x^2+9x+19)÷(x+5)
gayaneshka [121]
Since this can’t be factored easily, you have to use synthetic division. This makes the answer x+4+(-1/x+5)

6 0
3 years ago
50 POINTS for both questions
love history [14]

Answer:

3. i think 15.5

4. 140*

Step-by-step explanation:

in number 4, d is a vertical angle to the angle measured at 140.

in number 3, QV=SV, so 17=4x-1     18=4x    18/4=x   x=4.5

and TS=TQ, so 3(x) + 2 = 3(4.5) + 2 = 13.5 + 2 = 15.5 =TQ

6 0
3 years ago
Read 2 more answers
Evaluate the line integral using the fundamental theorem of line integrals. use a computer algebra system to verify your results
mario62 [17]
\dfrac{\partial f}{\partial x}=\cos x\sin y\implies f(x,y)=\sin x\sin y+g(y)

\dfrac{\partial f}{\partial y}=\sin x\cos y=\sin x\cos y+\dfrac{\mathrm dg}{\mathrm dy}
\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C

f(x,y)=\sin x\sin y+C

\displaystyle\int_{\mathcal C}\cos x\sin y\,\mathrm dx+\sin x\cos y\,\mathrm dy=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f\left(\frac{3\pi}2,\frac\pi2\right)-f(0,-\pi)=-1
7 0
2 years ago
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