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erica [24]
3 years ago
11

A rectangle has an area of 126.9m² . One of the sides is 2.7m in length. Work out the perimeter of the rectangle​

Mathematics
1 answer:
Mice21 [21]3 years ago
3 0

Answer:

99.4 m

Step-by-step explanation:

First, divide 126.9 by 2.7, to get the other length that you don't know. You should get 47. Then, add 47 by 47 (94) and add 2.7 to 2.7 (5.4) and add those together to get your answer, 99.4 meters

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harkovskaia [24]

Answer:

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Step-by-step explanation:

7 0
2 years ago
PLZ help me!!!! I have no idea how to do this!
sp2606 [1]

Answer:

a)y^b z^{(b-1)}

Step-by-step explanation:

Hope this helps :)

7 0
3 years ago
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The Venn diagram shows the results of two events resulting from rolling a number cube.
gulaghasi [49]

Answer:   P(A\cap B)=\frac{1}{3}

P(A)=\frac{1}{3}

P(B)=1

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Step-by-step explanation:

From the given figure it can be seen that

Total number on cube= n(S)=6

Intersection of A and B = n(A ∩ B)= 2

Therefore,

P(A\cap B)=\frac{n(A\cap B)}{n(s)}=\frac{2}{6}=\frac{1}{3}

Also, The number of elements in A = 2

Therefore,

P(A)=\frac{n(A)}{n(s)}=\frac{2}{6}=\frac{1}{3}

Similarly, The number of elements in B= 6

Therefore,

P(B)=\frac{n(B)}{n(s)}=\frac{6}{6}=1

The formula to find the conditional probability is given by :-

P(A|B)=\frac{P(A\cap B)}{P(B)}\\\\\Rightarrow P(A|B)=\frac{\frac{1}{3}}{1}=\frac{1}{3}

4 0
3 years ago
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Two column proofs Beginner's
Darina [25.2K]

LETS prove the 2nd part of the Question

Here concept of right angles is used

We can see BA is perp to BD

and BC is perp to BE

We have to prove angle 1 = angle 3

i will denote angle by a

therefore we need to prove a1 = a3

as BA is perp to BD hence angle between them will be 90 degree

a1 + a2 = 90 degree

Similarly BC is perp to BE

a2 + a3 = 90 degree

as both equations add up gives 90 degree so will equate them

a1 + a2 = a2 + a3

which means a1 = a3

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To learn more about Right Angles:

brainly.com/question/7116550

#SPJ1

3 0
10 months ago
PLEASE HELP!!! Find the equation , in the standard form of the line passing through the points (3,-4) and (5,1)
ExtremeBDS [4]
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ 3 &,& -4~) 
%  (c,d)
&&(~ 5 &,& 1~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-4)}{5-3}\implies \cfrac{1+4}{5-3}\implies \cfrac{5}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=\cfrac{5}{2}(x-3)\implies y+4=\cfrac{5}{2}x-\cfrac{15}{2}

\bf y=\cfrac{5}{2}x-\cfrac{15}{2}-4\implies y=\cfrac{5}{2}x-\cfrac{23}{2}\impliedby 
\begin{array}{llll}
\textit{now let's multiply both}\\
\textit{sides by }\stackrel{LCD}{2}
\end{array}
\\\\\\
2(y)=2\left( \cfrac{5}{2}x-\cfrac{23}{2} \right)\implies 2y=5x-23\implies \stackrel{standard~form}{-5x+2y=-23}
\\\\\\
\textit{and if we multiply both sides by -1}\qquad 5x-2y=23

side note:  multiplying by the LCD of both sides is just to get rid of the denominators
5 0
3 years ago
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