Answer:3/8
Step-by-step explanation:
Answer:

Step-by-step explanation:
see the attached figure to better understand the problem
step 1
Find the measure of angle KOM
In the triangle KOM
we have


Applying the law of cosines







step 2
Find the measure of the arc KM
we know that
----> by central angle
we have

so

step 3
Find the measure of angle KLM
we know that
The inscribed angle is half that of the arc comprising
![m\angle KLM=\frac{1}{2}[arc\ KM]](https://tex.z-dn.net/?f=m%5Cangle%20KLM%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20KM%5D)
we have

substitute
![m\angle KLM=\frac{1}{2}[106.26^o]](https://tex.z-dn.net/?f=m%5Cangle%20KLM%3D%5Cfrac%7B1%7D%7B2%7D%5B106.26%5Eo%5D)

Hi! I know for sure that a and d are equivalent to the expression which is not what you are looking for. This is because 11 times 8 gives you the 88 on a and if you multiply the 5 also by 8 you get 40 so a is not the answer. The reason I multiply both by the same number and got the equivalency is because, "What you do to one side, you do to the other." Same thing with d. My answer would be B because you can't change the variable to a different number. You can't just give the five the y and make it mean the same. The answer is B.

To solve the problem find the value of (45)^2 at first


The answer is 25 with the remainder 75

You can simplify the fraction to be 25/26